卸下ArrayList的元素 [英] Remove elements from ArrayList

问题描述

我要删除的ArrayList 元素，但我没有通过它走了。我不得不删除元素也在的ArrayList 可用。总之，我必须从另外一个数组列表中删除一个数组列表。例如假设

I have to remove elements from ArrayList, but I have not gone through it. Elements which I have to remove are also available in ArrayList. In short, I have to remove one Array List from another Array List. e.g. Suppose

ArrayList<String> arr1= new ArrayList<String>();
ArrayList<String> arr2 = new ArrayList<String>();
arr1.add("1"); 
arr1.add("2"); 
arr1.add("3"); 

arr2.add("2"); 
arr2.add("4"); 

现在，我不得不删除这是从ARR1 ARR2元素。所以，我有最后的答案为1和3。
需要做什么？

Now, I have to remove elements which are in arr2 from arr1. So, that I have final answer as 1 and 3. What needs to be done?

推荐答案

阅读的在两个列表中删除常见元素的Java

低于code使用

List<String> resultArrayList = new ArrayList<String>(arr1);
resultArrayList.removeAll(arr2);

---

，或者可以通过

---

Or can be done by

arr1.removeAll(arr2)

---

SO意见后

---

After SO comments

我用下面的code

ArrayList<String> arr1= new ArrayList<String>();
        ArrayList<String> arr2 = new ArrayList<String>();
        arr1.add("1"); 
        arr1.add("2"); 
        arr1.add("3"); 

        arr2.add("2"); 
        arr2.add("4"); 

        System.out.println("Before removing---");
        System.out.println("Array1 : " + arr1);
        System.out.println("Array2 : " + arr2);
        System.out.println("Removing common ---");
        List<String> resultArrayList = new ArrayList<String>(arr1);
        resultArrayList.removeAll(arr2);                
        System.out.println(resultArrayList);

和获得输出为

Before removing---
Array1 : [1, 2, 3]
Array2 : [2, 4]
Removing common ---
[1, 3]

那么，什么是不是在你身边的工作？

So what is not working at your side?

了解更多关于<一个href=\"http://stackoverflow.com/questions/3846326/how-do-you-remove-the-overlapping-contents-of-one-list-from-another-list\">How你从另一个列表中删除一个列表的内容重叠？

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