removeObjectsInRange 的 Swift 等效项: [英] Swift Equivalent of removeObjectsInRange:

问题描述

在跟踪 Swift 等效项时遇到一些麻烦:

Having a little trouble tracking down the Swift equivalent of:

//timeArray and locationArray are NSMutableArrays
NSRange removalRange = NSMakeRange(0, i);

[timeArray removeObjectsInRange:removalRange];
[locationArray removeObjectsInRange:removalRange];

我看到 Swift 在 API 中确实有一个调用:typealias NSRange = _NSRange 但我还没有通过那部分.有什么帮助吗?

I see that Swift does have a call in the API: typealias NSRange = _NSRange but I haven't got past that part. Any help?

推荐答案

除了 Antonio 的回答，您还可以只使用范围运算符:

In addition to Antonio's answer, you can also just use the range operator:

var array = [0, 1, 2, 3, 4, 5]
array.removeRange(1..<3)
// array is now [0, 3, 4, 5]

• 半闭区间运算符 (1..<3) 包括 1，最多但不包括 3(所以 1-2).
• 全范围运算符 (1...3) 包括 3(即 1-3).
• The half-closed range operator (1..<3) includes 1, up to but not including 3 (so 1-2).
• A full range operator (1...3) includes 3 (so 1-3).

这篇关于removeObjectsInRange 的 Swift 等效项:的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！