寻找 Perl 习惯用法来检查 $self 是一个类还是一个对象 [英] Seek Perl idiom to check that $self is a class or object
问题描述
在 Perl 中,我刚刚被类似于下面的错误的东西咬了一口:
In Perl, I just got bitten by something that looked like the bug below:
package Foo;
sub method {
my $self = shift;
my @args = @_;
...
}
我把它称为子程序,而不是方法:
where I called it as a subroutine, not a method:
Foo::method( "arg1", "arg2" );
而不是将其作为方法调用 - 在这种情况下,它是一个类方法":
rather than calling it as a method - in this case, it was a "class method":
Foo->method( "arg1", "arg2" );
调用 Foo::method("arg1","arg2") 导致arg1"被丢弃.
Calling Foo::method("arg1","arg2") resulted in "arg1" getting dropped.
对象方法"可能会出现类似的考虑:
Similar considerations can arise with an "object method":
my $object = Foo->new();
$obj->method( "arg1", "arg2" );
是否有一种友好、简洁的 Perl 习惯用法来检查第一个参数,通常称为 $self
,实际上是类(包)和/或类/包中的对象名字?
Is there a friendly, concise, Perl idiom for checking that the first argument, conventionally called $self
, is in fact an object in the class (package), and/or the class/package name?
我想出的最好的是:
package Foo;
sub method {
my $self = ($_[0]->isa(__PACKAGE__) ? shift @_ : die "...error message...";
my @args = @_;
...
}
这并不比
package Foo;
sub method {
my $self = shift;
die "...error message..." if $self->isa(__PACKAGE__);
my @args = @_;
...
}
或
package Foo;
use Carp::Assert;
sub method {
my $self = shift;
assert($self->isa(__PACKAGE__));
my @args = @_;
...
}
<小时>
注意事项:
Notes:
我了解 Perl 签名,但不喜欢使用实验性功能.
I know about Perl signatures, but dislike using experimental features.
我知道使用属性
和:method
.这是最好的方式吗?对不断发展的"功能的类似担忧.
I know about use attributes
and :method
. Is that the best way to go? Similar concerns about "evolving" features.
我知道 Moose - 但我不认为 Moose 会强制执行此操作.(我是不是错过了什么.)
I know about Moose - but I don't think that Moose enforces this. (Did I miss anything.)
Perl 的问题在于有很多方法可以做某事.
The problem with Perl is that there are so many ways to do something.
推荐答案
最好的答案是不要在一个包中混合函数和方法.众所周知,混合模块"是有问题的.您可能想要创建函数的所有内容都应该是类方法调用.
The best answer is to not mix functions and methods in a single package. "Hybrid modules", as they're known, are problematic. Everything which you might want to make a function should instead be a class method call.
在日常编程中应该几乎不需要完全限定函数调用.
There should be little need to fully qualify a function call in day-to-day programming.
最简洁的方法是使用 Moops 这是使用 Moose 语法的新方法-糖.
The most concise way is to use Moops which is the new way to use Moose with syntax-sugar.
use Moops;
class Foo {
method something() {
print("something called\n");
}
}
Foo->new->something();
Foo::something();
# something called
# Invocant $self is required at /Users/schwern/tmp/test.plx line 10.
Moops 被标记为不稳定,但这是界面,而不是签名本身.签名已经存在并在生产中使用了很长时间,比它们内置的时间更长.更令人担忧的是已经有一年多没有发布了,但是作者写了好东西.您的来电.
Moops is marked as unstable, but that's the interface, not the signatures themselves. Signatures have been around and usable in production for a long time, longer than they've been built in. More worrying is there hasn't been a release in over a year, however the author writes good stuff. Your call.
否则,就像其他任何事情一样,编写一个函数.
Otherwise, like with anything else, write a function.
use Carp;
use Scalar::Util qw(blessed);
sub check_invocant {
my $thing = shift;
my $caller = caller;
if( !defined $thing ) {
croak "The invocant is not defined";
}
elsif( !ref $thing ) {
croak "The invocant is not a reference";
}
elsif( !blessed $thing ) {
croak "The invocant is not an object";
}
elsif( !$thing->isa($caller) ) {
croak "The invocant is not a subclass of $caller";
}
return $thing;
}
由于这会返回调用者并为您处理异常,因此可以非常简洁地使用.
Since this returns the invocant and handles the exception for you it can be used very concisely.
package Foo;
sub method {
my $self = ::check_invocant(shift);
...
}
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