call_user_func(array($this, $method), $par) 来自父的构造函数? [英] call_user_func(array($this, $method), $par) from parent's constructor?

问题描述

class Parent
{

  public function __construct($method) {
    call_user_func(array($this, $method), 1);
  }

}

class Child extends Parent
{

  public function __construct($method) {
    parent::__construct($method);
  }

  protected function call_me_on_construct($par) { 
    echo $par;
  }

}

正在创建 $child = new Child("call_me_on_construct"); 的实例；我想调用 call_me_on_construct 方法.问题是 Parent 的构造函数对 $this 一无所知.什么是更好的方法?

Creating instance of $child = new Child("call_me_on_construct"); I want call_me_on_construct method to be called. The problem is Parent's constructor know nothing about $this. What is better way to do it?

谢谢.

推荐答案

它知道 $this.代码中唯一的错误是您使用了保留关键字 parent

It knows about $this. The only error in your code is that you use reserved keyword parent

class Ancestor
{

  public function __construct($method) {
    call_user_func(array($this, $method), 1);
  }

}

class Child extends Ancestor
{

  public function __construct($method) {
    parent::__construct($method);
  }

  protected function call_me_on_construct($par) { 
    echo $par;
  }

}

$c = new child("call_me_on_construct");

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