mixins 可以访问它们在 Dart 中混合的类的状态吗? [英] Can mixins access the state of the class they're mixed with in Dart?

问题描述

mixin 可以访问它们在 Dart 中混合的类的状态吗?

Can mixins access the state of the class they're mixed with in Dart?

推荐答案

是的，通过使用 on 关键字.此示例说明:

Yes, through the use of on key word. This example illustrates:

void main() {
  final person = Bob();
  print(person.age);
  print(person.ageInside);
  // output will be 31, 13
}

mixin Comedian on Person {
  // no need to declare age variable here, it finds it through `on`
  @override
  int get ageInside {
    return age - 18;
  }
}

class Person {
  int age;
  int get ageInside {
    return age;
  }
  Person(this.age);
}

class Bob extends Person with Comedian {
  Bob() : super(31);
}

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