我如何优化这个简单的 python pygame 代码 [英] How could I optimise this simple python pygame code
问题描述
我面临着使用 pygame 制作游戏的挑战(我正在制作蛇,所以它应该很容易......但我从未使用过 pygame)所以使用更高效的语言不是一种选择.所以我的问题是我更新蛇网格太慢了,而且我在 pygame 中没有足够的经验来解决这个问题,任何人都可以提供帮助.另外作为一个说明,如果我只填充网格,它就不会在 Snake 后面清除.使用 python 3.8
I've been set a challenge to make a game using pygame ( I am making snake so it should be easy... but I've never used pygame) so using a more efficient language isn't an option.So my question is that I updating the snake grid is too slow and I'm not experienced enough in pygame to fix this, can anyone who is help.Also as a note if I only fill the grid it doesn't clear behind the Snake. Using python 3.8
import pygame
import time
import random
pygame.init()
display_width = 800
display_height = 600
display = pygame.display.set_mode((display_width,display_height))
pygame.display.set_caption("Snake")
pureblue = (0,0,255)
purered = (255,0,0)
puregreen = (0,255,0)
white = (255,255,255)
black = (1,1,1)
grey = (50,50,50)
darkgrey = (25,25,25)
clock = pygame.time.Clock()
snake_block = 10
snake_speed = 30
font_style = pygame.font.SysFont(None, 50)
def drawGrid():
blockSize = 10
for x in range(display_width):
for y in range(display_height):
rect = pygame.Rect(x*blockSize, y*blockSize,blockSize, blockSize)
pygame.draw.rect(display, darkgrey, rect, 1)
def message(msg, colour):
text = font_style.render(msg, True, colour)
display.blit(text, [display_width/2, display_height/2])
def SnakeGameLoop():
game_over = False
X = display_width/2
Y = display_height/2
X_change = 0
Y_change = 0
while not game_over:
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
X_change = -10
Y_change = 0
elif event.key == pygame.K_RIGHT:
X_change = 10
Y_change = 0
elif event.key == pygame.K_UP:
X_change = 0
Y_change = -10
elif event.key == pygame.K_DOWN:
X_change = 0
Y_change = 10
if X >= display_width or X < 0 or Y >= display_height or Y < 0:
game_over = True
X += X_change
Y += Y_change
display.fill(grey)
drawGrid()
pygame.draw.rect(display,puregreen,[X,Y,10,10])
pygame.display.update()
clock.tick(15)
message("You lost", purered)
pygame.display.update()
time.sleep(2)
pygame.quit()
quit()
SnakeGameLoop()
推荐答案
为了提高游戏的性能,在 pygame.Surface
具有屏幕大小的对象,之前应用程序循环:
To improve the game's performance, draw the grid on a pygame.Surface
object with the size of the screen, before the application loop:
def drawGrid(surf):
surf.fill(grey)
blockSize = 10
for x in range(display_width):
for y in range(display_height):
rect = pygame.Rect(x*blockSize, y*blockSize,blockSize, blockSize)
pygame.draw.rect(surf, darkgrey, rect, 1)
grid_surf = pygame.Surface(display.get_size())
drawGrid(grid_surf)
blit
在显示器上每帧绘制一次表面而不是每帧绘制一次网格,在应用程序循环中:
def SnakeGameLoop():
# [...]
while not game_over:
# [...]
display.blit(grid_surf, (0, 0))
pygame.draw.rect(display,puregreen,[X,Y,10,10])
pygame.display.update()
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