问题在数场ArrayList和保存 [英] Problem In count field in Arraylist and save it

问题描述

好，我有这个价值一个ArrayList

well, I have an ArrayList with this values

ACU
ACU
ACU
ACU
ACY
ACY
AER
AER
AER
AGC

我需要得到每个单词的项目数，因此对于

I need to get the number of items of each Word, so for

• ACU我们将获得4，


• ACY我们将得到2，


• AER我们将获得3


• AGC我们将获得1。

通常一个字重复的数目是可变
所以另一次ACU可以是1，和ACY可以是100 ..

Generally the number a word is repeated is a variable so another time ACU could be 1,and ACY could be 100..

所以，我有一个类，以保持价值观whatWordAND的howmany

So., I have a class to keep the values "whatWord" AND "howMany"

public class Word {

private String whatWord;
private int howMany;

public  cVOPlaza(String whatWord, int  howMany){
  this.whatWord = whatWord;
  this.howMany= howMany;     
}

public String getwhatWord() {
  return whatWord;
}

public void setwhatWord(String whatWord) {
   this.whatWord = whatWord;
}

public int gethowMany() {
   return howMany;
 }

public void sethowMany(int howMany) {
   this.howMany = howMany;
 } 
}

我在这里卡住了，因为我知道部分GET（I + 1）在以下code会导致错误，你知道值不存在，但我不知道该怎么办...

I am stuck here, because I know the part get(i+1) in the following code will cause error, You know value does not exist, but then I dont know what to do...

ArrayList<Word> arrayWords = new ArrayList<Word>();
 int cuantos = 0;
     for (int i=0;i<OriginalList.size();i++) {
     String word1  = OriginalList.get(i).getWord();
     String word2 = OriginalList.get(i+1).getWord();
             if (word1.equals(word2)){
                       //this counter is bad here... 
                       //where do i increment it??
         howMany++;
         Word a = new Word(word1,howMany);
         ///....DONT KNOW WHERE TO ADD THE OBJECT 
                        //to the list
                         //arrayWords.add(a)
      }
        }

据推测，后为code我将获得

It is supposed that after the for code I will get

ACU 4,
ACY 2,
AER 3,
AGC 1.

首先，我试图做一个HashMap试试，请帮我这个code：

First I tried to do a HashMap try, please help me with this code:

 HashMap table = new HashMap();
    int value=0;
    String key=null;

   //INITIALIZE HASH??? LIKE THIS
    for (int i = 0; i < OriginalList.size; i++) {
        table.put(0,OriginalList.get(i).getWord());      
    }


         String word1=null;
         ArrayList<Word> arrayWords = new ArrayList<Word>();
         //LOOP FOR SEARCHING
         for (int i = 0; i < OriginalList.size(); i++) {
               key = OriginalList.get(i).getWord();
               if (table.containsKey(key)) { 
                       word1 = (String) table.get(key);
                       value++;
               }else {
                      word1 = (String) table.get(key);
                      value=1
               }
             //Add result??
             Word a = new Word(word1,value);
         }

在此先感谢。

推荐答案

这可能是矫枉过正，你想要做什么。你可以更简单地创建一个地图，有三个字母的字符串作为关键和伯爵的价值。然后，只需遍历你的ArrayList

That might be overkill for what you want to do. You could more simply create a map that has the three-letter string as the key and the count as the value. Then just iterate over your ArrayList:

Map<String, Integer>wordCount = new HashMap<String, int>();
for(String seq : yourWordList){
    // increment the count of the word by first obtaining its count,
    // and then incrementing it. Paranthesis for clarity
    wordCount.put(seq, (wordCount.get(seq)) + 1);
}

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