pandas 获得“索引"给定索引的系列标签 [英] Pandas get the "index" label of a series given an index
问题描述
好的,由于缺乏词汇,这很令人困惑.
Ok, so this is confusing because of a lack of vocabulary.
Pandas 系列有一个索引和一个值:所以 'series[0]' 包含 (index,value).
Pandas series have an index and a value: so 'series[0]' contains (index,value).
如何通过索引系列从系列中获取索引(在我的情况下是日期)?这真的是一个非常简单的想法……它只是用索引"这个词加密了.哈哈.
How do I get the index (in my case it is a date), out of the series by indexing the series? This is really a very simple idea...it is just encrypted by the word "index." lol.
所以,换个说法,
当我的系列按日期索引时,我需要系列中第一个条目和最后一个条目的日期.
I need the date of the first entry in my series and the last entry, when my series is indexed by date.
为了清楚起见,我有一个按日期索引的系列,所以当我打印出来时,它会打印:
just to be clear, I have a series indexed by date, so when I print it out, it prints:
12-12-2008 1.2
12-13-2008 1.3
...
并打电话
df.ix[0] -> 1.2
我需要:
df.something[0] -> 12-12-2008
推荐答案
明白了.
df.index[0]
在索引 0 处产生标签.
yields the label at index 0.
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