使用字典替换 Pandas 数据帧上给定索引号的列值 [英] Using a dictionary to replace column values on given index numbers on a pandas dataframe

问题描述

考虑以下数据框

df_test = pd.DataFrame( {'a' : [1, 2, 8], 'b' : [np.nan, np.nan, 5], 'c' : [np.nan, np.nan, 4]})
df_test.index = ['one', 'two', 'three']

给出

      a  b   c
one   1 NaN NaN
two   2 NaN NaN
three 8  5   4

我有一个列 b 和 c 的行替换字典.例如:

I have a dictionary of row replacements for columns b and c. For example:

{ 'one': [3.1, 2.2], 'two' : [8.8, 4.4] }

其中 3.1 和 8.8 替换 b 列，2.2 和 4.4 替换 c 列，结果为

where 3.1 and 8.8 replaces column b and 2.2 and 4.4 replaces column c, so that the result is

      a  b   c
one   1 3.1 2.2
two   2 8.8 4.4
three 8  5   4

我知道如何使用 for 循环进行这些更改:

I know how to make these changes with a for loop:

index_list = ['one', 'two']
value_list_b = [3.1, 8.8]
value_list_c = [2.2, 4.4]
for i in range(len(index_list)):
    df_test.ix[df_test.index == index_list[i], 'b'] = value_list_b[i]
    df_test.ix[df_test.index == index_list[i], 'c'] = value_list_c[i]

但我相信有一种更好更快的方式来使用字典！

but I'm sure there's a nicer and quicker way to use the dictionary!

我想可以使用 DataFrame.replace 方法来完成，但我无法弄清楚.

I guess it can be done with the DataFrame.replace method, but I couldn't figure it out.

感谢您的帮助，

光盘

推荐答案

您正在寻找 pandas.DataFrame.update.在您的情况下唯一的扭曲是您将更新指定为行字典，而 DataFrame 通常是从列字典构建的.orient 关键字可以解决这个问题.

You are looking for pandas.DataFrame.update. The only twist in your case is that you specify the updates as a dictionary of rows, whereas a DataFrame is usually built from a dictionary of columns. The orient keyword can handle that.

In [24]: import pandas as pd

In [25]: df_test
Out[25]: 
       a   b   c
one    1 NaN NaN
two    2 NaN NaN
three  8   5   4

In [26]: row_replacements = { 'one': [3.1, 2.2], 'two' : [8.8, 4.4] }

In [27]: df_update = pd.DataFrame.from_dict(row_replacements, orient='index')

In [28]: df_update.columns = ['b', 'c']

In [29]: df_update
Out[29]: 
        b     c
one   3.1   2.2
two   8.8   4.4

In [30]: df_test.update(df_update)

In [31]: df_test
Out[31]: 
       a    b    c
one    1  3.1  2.2
two    2  8.8  4.4
three  8  5.0  4.0

pandas.DataFrame.from_dict 是一个特定的 DataFrame 构造函数，它为我们提供了 orient 关键字，如果您只说 DataFrame(...)，则不可用.由于我不知道的原因，我们无法将列名 ['b', 'c'] 传递给 from_dict，因此我在单独的步骤中指定了它们.

pandas.DataFrame.from_dict is a specific DataFrame constructor that gives us the orient keyword, not available if you just say DataFrame(...). For reasons I don't know, we can't pass column names ['b', 'c'] to from_dict, so I specified them in separate step.

这篇关于使用字典替换 Pandas 数据帧上给定索引号的列值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！