如预期Collections.sort不排序的ArrayList [BeanShell中，爪哇，JMeter的] [英] Collections.sort not sorting ArrayList as expected [beanshell, Java, JMeter]

问题描述

我有我正在使用的BeanShell处理器（JMeter的），其中一些Java code。这个Java code是简单而有效。它应该只是排序数字数组列表，但它给奇怪的行为：

I have some Java code which I am using in Beanshell processor (JMeter). This java code is simple and valid. It should simply sort the numeric arraylist but it is giving strange behavior:

// Input data is like below:
   student_id_RegEx_1=13
   student_id_RegEx_11=4
   student_id_RegEx_12=23
   student_id_RegEx_13=24

// CREATE ARRAY LIST AND STORE ELEMENTS IN IT
ArrayList strList = new ArrayList();
for (int i=0;i<25; i++){
strList.add(vars.get("student_id_RegEx_" + String.valueOf(i+1)));
}

// Print the ArrayList created by above method [output is]
vars.putObject("ArrayListBeforeSorting",strList);
ArrayListBeforeSorting=[13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 4, 23, 24, 25, 26, 27, 28, 29, 5, 6, 7, 8, 9, 10, 11]


// Sort the ArrayList 
Collections.sort(strList);

//Print the sorted ArrayList [below is output]
vars.putObject("ArrayListAfterSorting",strList);
ArrayListAfterSorting=[10, 11, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 4, 5, 6, 7, 8, 9]

观察 28，29，4，5，6，7，8，9，10，11 是在sortedArrayList结束。我期待 4，5，6，7，8，9，10，11，12等我不明白后面这种奇怪的行为的原因。难道是因为一些问题与'阵列输入数据？ Collections.sort似乎做工精细;当我创建一个样品的ArrayList自己。此行为和解决方案的任何评论都将AP preciated。谢谢你。

Observe the 28, 29, 4, 5, 6, 7, 8, 9, 10, 11 at end of sortedArrayList. I was expecting 4, 5, 6, 7, 8, 9, 10, 11, 12 and so on I cannot understand the reason behind this strange behavior. Could it be because of some issue with 'array input data'? Collections.sort seems to work fine; when I create a sample arraylist myself. Any comments on this behavior and solution would be appreciated. Thanks.

推荐答案

不需要将String类型的值，并将其保存为数字：

Instead of saving values of type String, save them as numbers:

String strValue = vars.get("student_id_RegEx_" + String.valueOf(i+1));
strList.add(Integer.parseInt(strValue));

排序为字符串的工作原理是比较每个字符，一个接一个，例如：

Sorting as Strings works by comparing each character, one by one, for example:

2 4 5
| | | |
2 2 3 3

2 = 2
4 > 2 - therefore, "245" is "bigger" than "2233"

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