将元组扩展为参数 [英] Expanding tuples into arguments

问题描述

有没有办法将 Python 元组扩展为函数 - 作为实际参数?

Is there a way to expand a Python tuple into a function - as actual parameters?

例如，这里 expand() 发挥了作用:

For example, here expand() does the magic:

some_tuple = (1, "foo", "bar")

def myfun(number, str1, str2):
    return (number * 2, str1 + str2, str2 + str1)

myfun(expand(some_tuple)) # (2, "foobar", "barfoo")

我知道可以将 myfun 定义为 myfun((a, b, c))，但当然可能会有遗留代码.谢谢

I know one could define myfun as myfun((a, b, c)), but of course there may be legacy code. Thanks

推荐答案

myfun(*some_tuple) 完全符合您的要求.* 运算符简单地解包元组(或任何可迭代对象)并将它们作为位置参数传递给函数.阅读有关解包参数的更多信息.

myfun(*some_tuple) does exactly what you request. The * operator simply unpacks the tuple (or any iterable) and passes them as the positional arguments to the function. Read more about unpacking arguments.

这篇关于将元组扩展为参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！