powershell 通过 system.object[] 无需展开 [英] powershell pass system.object[] without unrolling

问题描述

关于如何在不展开 Get-PSCallStack 的情况下传递 Get-PSCallStack 的任何想法.它似乎是一个 system.object[] 但从我在网上阅读的内容来看，它们在通过和展开"时不会保持完整.我试着在前面放一个逗号来防止它，但没有用.

any ideas on how I can pass the Get-PSCallStack with out having it unroll. It appears to be a system.object[] but from what i have read online they don't remain intact when passed and " unroll ". I tried placing a comma in front to prevent it but that did not work.

function Pass-Callstack ([System.Object]$arg0) {
Write-Host 'Start Pass-Callstack'
$psCallStack = $arg0
$psCallStackType = $psCallStack.GetType()
$psCallStackLength = $psCallStack.Length
$psCallStackCommand0 = $psCallStack[0].command 
$psCallStackCommand1 = $psCallStack[1].command
Write-Host $psCallStackType
Write-Host $psCallStackLength
Write-Host $psCallStackCommand0
Write-Host $psCallStackCommand1
$arg0 | gm
}

function Describe-Callstack {
Write-Host 'Start Describe-Callstack'
$psCallStack = (Get-PSCallStack)
$psCallStackType = $psCallStack.GetType()
$psCallStackLength = $psCallStack.Length
$psCallStackCommand0 = $psCallStack[0].command 
$psCallStackCommand1 = $psCallStack[1].command
Write-Host $psCallStackType
Write-Host $psCallStackLength
Write-Host $psCallStackCommand0
Write-Host $psCallStackCommand1
$psCallStack | gm
}
Describe-Callstack
Pass-Callstack (,$psCallStack)

推荐答案

当你将一个参数传递给一个函数而不用管道传递它时，不会展开集合，例如

When you pass an argument into a Function without piping it in there is no unrolling of collections e.g.

function ArgShape($p)
{
    $p.GetType().Fullname
    $p.Rank
    $p.Length
    $p[0].GetType().Fullname
}

ArgShape (Get-PSCallstack)

System.Object[]
1
2
System.Management.Automation.CallStackFrame

此外，如果您希望参数数组传递给 Pass-Callstack，您可以像这样指定:

Also, if you are expecting an array for the parameter to Pass-Callstack you can specify that like so:

function Pass-Callstack([object[]]$array)

注意使用系统".命名空间前缀是可选的.如果 PowerShell 找不到类型，它将在前面加上.此外，将参数指定为 [object] 本质上是无操作的，因为这是默认类型.即 [object]$arg0 与 $arg0 相同.

Note that the use of the "System." namespace prefix is optional. PowerShell will prepend that if it can't find the type. Also, to specify a parameter as [object] is essentially a no-op because that is the default type. That is [object]$arg0 is the same as $arg0.

您还将 $null 传入 Pass-Callstack(尽管包装在单个元素数组中).变量 $psCallStack 是该函数的私有变量，在函数外部不可见，除非您确实在它前面加上了像 $script:psCallStack 这样的修饰符.一般来说，我不推荐这种方法.您应该像这样从 Describe-Callstack 输出 $pscallstack:

You are also passing in $null into Pass-Callstack (albeit wrapped in a single element array). The variable $psCallStack is private to the function and not visible outside it unless you do prepend it with a modifier like $script:psCallStack. In general I don't recommend this approach. You should output $pscallstack from Describe-Callstack like so:

function Describe-Callstack { 
Write-Host 'Start Describe-Callstack' 
$psCallStack = (Get-PSCallStack) 
$psCallStackType = $psCallStack.GetType() 
$psCallStackLength = $psCallStack.Length 
$psCallStackCommand0 = $psCallStack[0].command  
$psCallStackCommand1 = $psCallStack[1].command 
Write-Host $psCallStackType 
Write-Host $psCallStackLength 
Write-Host $psCallStackCommand0 
Write-Host $psCallStackCommand1 
$psCallStack 
}

然后将函数调用的输出赋值给一个变量:

Then assign the output of the function call to a variable:

$cs = Describe-Callstack 

并将其传递到 Pass-Callstack 例如:

And pass that into Pass-Callstack e.g.:

Pass-Callstack $cs

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