将字符串变量作为逗号分隔列表传递给函数参数 [英] Pass String Variable to Function Argument as Comma Separated List

问题描述

我有一个 PowerShell 函数，它通过逗号分隔列表接受单个参数的多个值，如下所示:

I've got a PowerShell function that accepts multiple values for a single argument via a comma separated list, like so:

test-function -Targets 127.0.0.1, 8.8.8.8, fake.fqdn.com -FileName "c:\results.csv"

这是参数部分:

function test-function {
    param(
        [string[]]$Targets
        [string]$FileName
    )
}

我试图将一个数组作为多个 Target 参数放入，所以我将它们放入一个变量中，如下所示:

I'm trying to put an array in as multiple Target arguments, so I've put them into a single variable like so:

foreach ($target in $arrayTargets) { $temp = $temp + ", $Target" }
$Targets = $temp -replace "^, ", ""

这将导致所需的127.0.0.1, 8.8.8.8, fake.fqdn.com"作为变量 $Targets 中的字符串.

This would result in the required "127.0.0.1, 8.8.8.8, fake.fqdn.com" as a string in the variable $Targets.

当我尝试执行引用 $Targets 变量的函数时，该函数将 $Targets 解释为一个条目，而不是多个条目.这是我尝试过的相同结果:

When I try to execute the function referencing the $Targets variable, the function interprets $Targets as if it's a single entry, not multiple. This is what I've tried with the same results:

test-function -Targets $Targets -FileName "c:\results.csv"
test-function -Targets "$Targets" -FileName "c:\results.csv"

我还尝试了几种不同的 ArgList 方法:

I've also tried an ArgList several different ways:

$ArgList = "-Targets $Targets -FileName `"c:\results.csv`""
test-function $ArgList

它不是将每个单独的数组条目作为参数，而是将整个字符串作为参数.

Instead of taking each individual array entry as an argument, it takes the entire string as the argument.

如何让这个函数接受一个数组作为多个目标?

How can I get this function to accept an array as multiple targets?

推荐答案

如果你有一个参数数组，就没有理由将它们打包成一个字符串传递给你的函数.只需传递数组.

If you have an array of arguments, there should be no reason to pack them into a string to pass to your function. Simply pass the array.

test-function -Targets $arrayTargets

要在 PowerShell 中将一组值分配给变量，只需分配一个逗号分隔的列表即可.注意要创建一个字符串数组，您应该确保将字符串放在引号中(单引号或双引号).以下所有内容都是等价的.

To assign an array of values to a variable in PowerShell, simply assign a comma-separated list. Note to make an array of strings, you should make sure to put the strings in quotes (single or double). All of the following are equivalent.

$arr = @("127.0.0.1", "8.8.8.8", "fake.fqdn.com")
$arr = ('127.0.0.1', '8.8.8.8', 'fake.fqdn.com')
$arr = "127.0.0.1", '8.8.8.8', "fake.fqdn.com"

如果您出于任何原因需要将数组转换为逗号分隔的字符串，则无需使用 foreach 循环构建它.而是使用 -join 运算符.

If you need your array to convert to a comma-separated string for any reason, there's no need to build it with a foreach loop. Instead use the -join operator.

PS> $string = $arr -join ', '
PS> $string
127.0.0.1, 8.8.8.8, fake.fqdn.com

但您可能只希望以这种形式显示数组.如上所示，最好将其保留为数组形式以传递给函数.您甚至可以使用 -split 运算符从字符串中取回数组.

But you will probably only want your array in this form to display it. As shown above, it's best to keep it in array form to pass to a function. You can even get the array back from the string using the -split operator.

PS> $string -split ', '
127.0.0.1
8.8.8.8
fake.fqdn.com

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