XPath:递归祖先搜索 [英] XPath: Recursive Ancestor Search

问题描述

选择当前节点后，我希望找到一个元素 [./name] 并返回文本内容.如果当前选择的节点中不存在元素 我希望检查父元素 [./parent::name] 等等递归直到根，返回元素所在的最近父元素的值.

With my current node selected I wish to find an element <name> [./name] and return the text content. If an element <name> does not exist in the currently selected node I wish to check the parent element [./parent::name] and so on recursively up to the root, returning the value of the nearest parent where the element exists.

可以用 XPath 完成吗?

Can it be done with XPath?

推荐答案

(我第一次误解了问题)

( I misinterpreted the question the first time)

我建议使用

ancestor-or-self::name[1]

这将查找所有 name 元素，从 self、parent 等开始，并按照与 self 的距离递增对它们进行排序.所以选择 [1] 会给你最接近的一个.

This finds all name elements, starting with self, parent, and so on, and orders them in increasing distance from self. So selecting [1] gives you the nearest one.

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