如果值包含单词的复数形式,如何删除一行? [英] How to delete a row if value include plural form of the words?
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问题描述
如果值包含单词的复数形式,并且仅存在单词的单形式,则删除一行,例如DataFrame包含'test'和'tests'或'company'和'companys',即删除测试"和公司".接下来我想应用另一个规则构词规则
Delete a row if value include the plural form of the words and only if exists the single form of word too, for example DataFrame contains 'test' and 'tests' or 'company' and 'companies', that is will be delete 'tests' and 'companies'. And next I want to apply another rules word formation rules
原始数据框
d0 = [{'word':'test', 'count':22}, {'word':'tests', 'count':11},{'word':'company', 'count':2},{'word':'companies', 'count':5}]
df0 = pd.DataFrame(d0)
理想的数据帧
d1 = [{'word':'test', 'count':22}, {'word':'company', 'count':11}]
df1 = pd.DataFrame(d1)
推荐答案
怎么样:
import nltk
nltk.download('wordnet')
from nltk.stem import WordNetLemmatizer
wnl = WordNetLemmatizer()
d0 = [{'word':'test', 'count':22}, {'word':'tests', 'count':11},{'word':'company', 'count':2},{'word':'companies', 'count':5},
{'word':'debris', 'count':5}]
def not_plural(word):
lemma = wnl.lemmatize(word, 'n')
not_plural = False if word is not lemma else True
return not_plural
df1 = df0[df0.word.apply(not_plural)]
df1
word count
0 test 22
2 company 2
4 debris 5
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