拆分字符串然后旋转结果 [英] Splitting a string then pivoting result

问题描述

如果从 .Net 应用程序传递一个字符串，如下所示

If have a string passed from a .Net application that looks like the below

2023|F66451,1684|648521,1684|600271,2137|019592

我已经开始使用下面的方法解析出字符串，但我需要旋转从 Split(被 * 包围)函数返回的数据，以便插入到 #tmpExceptions 表中

I have started to parse out the string using the method below but I need to Pivot the data returned from the Split ( surrounded by *'s) function in order to insert into the #tmpExceptions table

DECLARE @ExceptionsList as nvarchar(MAX)

SET @ExceptionsList = '2023|F66451,1684|648521,1684|600271,2137|019592'

SET NOCOUNT ON;

DECLARE @CurrentLineItem as nvarchar(255)

CREATE TABLE #ParsePassOne
(
    LineItem nvarchar(255)
)

CREATE TABLE #tmpExceptions
(
    AccountNumber int,
    ClaimNumber nvarchar(50)
)

INSERT INTO #ParsePassOne
    SELECT value FROM Split( ',' ,@ExceptionsList)

WHILE EXISTS(SELECT LineItem FROM #ParsePassOne)
    BEGIN
        SELECT TOP 1 @CurrentLineItem = LineItem FROM #ParsePassOne

        *******
            SELECT value FROM Split( '|' ,@CurrentLineItem) 
            *******

        DELETE FROM #ParsePassOne WHERE LineItem = @CurrentLineItem
    END

SELECT * FROM #tmpExceptions

DROP TABLE #ParsePassOne
DROP TABLE #tmpExceptions

到目前为止返回的数据如下所示.我只需要将数据透视到列，这样我就可以插入它.我该怎么办?

So far the data returned looks as below. I just need to pivot the data to columns so I can insert it. How do I go about this?

分割函数

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
--Creates an 'InLine' Table Valued Function (TVF)
ALTER FUNCTION [dbo].[Split] 
   (  @Delimiter varchar(5), 
      @List      varchar(8000)
   ) 
   RETURNS @TableOfValues table 
      (  RowID   smallint IDENTITY(1,1), 
         [Value] varchar(50) 
      ) 
AS 
   BEGIN

      DECLARE @LenString int 

      WHILE len( @List ) > 0 
         BEGIN 

            SELECT @LenString = 
               (CASE charindex( @Delimiter, @List ) 
                   WHEN 0 THEN len( @List ) 
                   ELSE ( charindex( @Delimiter, @List ) -1 )
                END
               ) 

            INSERT INTO @TableOfValues 
               SELECT substring( @List, 1, @LenString )

            SELECT @List = 
               (CASE ( len( @List ) - @LenString ) 
                   WHEN 0 THEN '' 
                   ELSE right( @List, len( @List ) - @LenString - 1 ) 
                END
               ) 
         END

      RETURN 

   END 

推荐答案

你可以用

select *
from
(
select * from #parsepassone
    cross apply dbo.Split( '|' ,lineitem)  
) src
pivot
(max(value) for rowid in ([1],[2]))p

或者用

insert #tmpExceptions (AccountNumber, ClaimNumber)
select [1],[2]
from
(
select e.rowid e, p.* from dbo.Split( ',' ,@ExceptionsList) e
    cross apply dbo.Split( '|' ,e.value) p ) s
pivot
(max(value) for rowid in ([1],[2]))p

这篇关于拆分字符串然后旋转结果的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！