使用Java读取名称中有空格的文件? [英] Read file with whitespace in name using Java?

问题描述

文件原名是1_00100 0042.jpg.我有问题:

The original name of file is 1_00100 0042.jpg. I have a problem:

java.net.URISyntaxException: Illegal character in path at index 49: file:///opt/storage/user-data/attachments/1_00100\ 0042.jpg

你能给我一些如何使用这个错误路径获取这个文件的解决方案吗?我知道 C# 有 Path 类.Java中有没有类似的东西?

Can you give me some solutions how to get this file using this bad path? I know that C# have Path class. Is there something similar in Java?

我尝试下一步但没有成功:

I tried to do next but not successfully:

private String replaceWhitespace(String str) {
    if (str.contains(" ")) {
        str = str.replace(" ", "%20");
    }
    return str;
}

推荐答案

使用文件，它适用于空格:

Use File, it works with whitespaces:

String path = "file:///opt/storage/user-data/attachments/1_00100\\ 0042.jpg";
File f = new File(path);

如果您想用 %20 替换空格，请使用正则表达式:

If you want to replace spaces with %20 then use regex:

path.replaceAll("\\u0020", "%20");

这篇关于使用Java读取名称中有空格的文件?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！