Os.path :你能解释一下这种行为吗? [英] Os.path : can you explain this behavior?

问题描述

我喜欢 Python，因为它包含电池，而且我经常使用内置函数来为我完成繁重的工作.

我一直很高兴使用 os.path 模块来处理文件路径，但最近我在 Ubuntu linux 下的 Python 2.5 上得到了意想不到的结果，同时处理表示 Windows 文件路径的字符串:

filepath = r"c:\ttemp\FILEPA~1.EXE"打印 os.path.basename(filepath)'c:\\ttemp\\FILEPA~1.EXE']打印 os.path.splitdrive(文件路径)('', 'c:\ttemp\\FILEPA~1.EXE')

WTF?

文件路径 = u"c:\ttemp\FILEPA~1.EXE" 和 filepath = "c:\ttemp\FILEPA~1.EXE" 的结果相同.

你有线索吗?Ubuntu 使用 UTF8，但我觉得它与它无关.也许我的 Python 安装搞砸了，但我没有对它进行任何我记得的特定调整.

解决方案

如果你想在 linux 上操作 Windows 路径，你应该使用 ntpath 模块(这是在 windows 上作为 os.path 导入的模块 - posixpath 被导入作为 os.path 在 linux)

<预><代码>>>>导入路径>>>文件路径 = r"c:\ttemp\FILEPA~1.EXE">>>打印 ntpath.basename(文件路径)FILEPA~1.EXE>>>打印 ntpath.splitdrive(文件路径)('c:', '\\ttemp\\FILEPA~1.EXE')

I love Python because it comes batteries included, and I use built-in functions, a lot, to do the dirty job for me.

I have always been using happily the os.path module to deal with file path but recently I ended up with unexpected results on Python 2.5 under Ubuntu linux, while dealing with string that represent windows file paths :

filepath = r"c:\ttemp\FILEPA~1.EXE"
print os.path.basename(filepath)
'c:\\ttemp\\FILEPA~1.EXE']
print os.path.splitdrive(filepath)
('', 'c:\ttemp\\FILEPA~1.EXE')

WTF ?

It ends up the same way with filepath = u"c:\ttemp\FILEPA~1.EXE" and filepath = "c:\ttemp\FILEPA~1.EXE".

Do you have a clue ? Ubuntu use UTF8 but I don't feel like it has something to do with it. Maybe my Python install is messed up but I did not perform any particular tweak on it that I can remember.

解决方案

If you want to manipulate Windows paths on linux you should use the ntpath module (this is the module that is imported as os.path on windows - posixpath is imported as os.path on linux)

>>> import ntpath
>>> filepath = r"c:\ttemp\FILEPA~1.EXE"
>>> print ntpath.basename(filepath)
FILEPA~1.EXE
>>> print ntpath.splitdrive(filepath)
('c:', '\\ttemp\\FILEPA~1.EXE')

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