在由数字组成的字符串中查找未知的重复模式 [英] Finding unknown repeating patterns in a string consisting numbers

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问题描述

我已经为此苦苦挣扎了一个星期.

I've been struggling with this for a week.

我有一个这样的字符串:1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1.....

I have a string like this: 1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1 1 0 1.....

我需要找到什么:1 1 0


示例 2:1 1 2 0 2 2 1 0 1 1 2 0 2 2 1 0 1 1 2 0 2 2 1 0 1 1 2 0 2 2 1 0 ....

我需要找到什么:1 1 2 0 2 2 1 0


示例 3:1 1 2 3 1 0 1 1 2 3 1 0 1 1 2 3 1 0 1 1 2 3 1 0 1 1 2 3 1 0...

112310


等等.等

我现在的代码:

private string tekrarArama(double[] mods)
        {
            string part1 = "";
            string part2 = "";

            string patern = "";


            int number1 = mods.Length;

            for (int i = 0; i < mods.Length; i++)
            {
                part1 = "";
                part2 = "";
                for (int j = 0; j < number1; j++)
                {

                    part1 += mods[j] + ",";
                }


                for (int k = 0; k < mods.Length; k++)
                {

                    part2 += mods[k] + ",";
                }


                int actualcount = Regex.Matches(part2, part1).Count;

                int count = part2.Replace(",", "").Length / part1.Replace(",", "").Length;


                if (part2.IndexOf(bolum1) >= 0 && actualcount == count )
                {
                    patern = part2.Substring(part2.IndexOf(part1),part1.Length);
                }

                number1--;


            }

            return patern;

        }

它创建字符串的两个副本,并在每次迭代中从其中一个字符串中一次删除 1 个字符,以找到最小的重复模式.

It creates two copies of the string and deletes 1 character at a time from one of the strings in each iteration, to find the smallest repeating pattern.

这是一团糟,根本不能很好地工作.我怎样才能做到这一点?提前致谢.

It's a mess and doesn't work very well at all. How can I do this? Thanks in advance.

推荐答案

如果您正在寻找简单的东西并且不需要最佳的复杂性,这里有一种简洁的方式来表示查询.

If you're looking for something simple and don't need optimal complexity, here's a concise way to represent the query.

string FindPattern(string text)
{
    if (text == null)
    {
        return null;
    }

    return Enumerable
        .Range(1, text.Length / 2)
        .Where(n => text.Length % n == 0)
        .Select(n => text.Substring(0, n))
        .Where(pattern => Enumerable
            .Range(0, text.Length / pattern.Length)
            .SelectMany(i => pattern)
            .SequenceEqual(text))
        .FirstOrDefault();
}

请注意,这里的复杂度在最坏的情况下是二次的,因此将其用于很长的字符串并不是一个好主意.

Note that the complexity here is quadratic in the worst case, so it's not a good idea to use it for very long strings.

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