RegEx 根据运算符拆分字符串并保留运算符作为答案 [英] RegEx to split string based on operators and retain operator in answer

问题描述

我想根据几个操作数拆分字符串.

I want to split string based on few operands.

例如字符串:a&&(b||c)

For e.g. String : a&&(b||c)

ANS : String[] {a,&&,(,||,c,)}

ANS : String[] {a,&&,(,||,c,)}

Java 正则表达式可以吗?如果是，那么如何?

IS it possible with java RegEx? If yes then how?

我尝试使用 [&&||()] regEx ，但它没有给出所需的输出.甚至我都不知道如何留住运营商.

I tried with [&&||()] regEx , but its not giving desired output. and even I am not sure how to retain operators.

如果我们有 &和|而不是 &&和 ||?

And what if we have & and | instead of && and || ?

推荐答案

您可以拆分:

(?<![&|])(?=[&|])|(?<=[&|])(?![&|])

• (?<![&|])(?=[&|]) 的意思是任何inter-char不是 前面是 & 或 | 但is 后面是 & 或 |";
• 相反，(?<=[&|])(?![&|]) 表示任何inter-charis 前面有 & 或 | 但ist 后跟 & 或|".
• (?<![&|])(?=[&|]) means "any inter-char that isn't preceded by & or | but that is followed by & or |";
• On the opposit, (?<=[&|])(?![&|]) means "any inter-char that is preceded by & or | but that isn't followed by & or |".

例如:

String pattern = "(?<![&|])(?=[&|])|(?<=[&|])(?![&|])";
String input = "a&&(b||c)";
String[] array = input.split(pattern);
System.out.println(Arrays.asList(array));

打印:

[a, &&, (b, ||, c)]

这篇关于RegEx 根据运算符拆分字符串并保留运算符作为答案的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！