python grep反向匹配 [英] python grep reverse matching

问题描述

我想构建一个小的python脚本，它基本上与grep相反.我想匹配没有searched_string"的目录/子目录中的文件.

I would like to build a small python script that basicaly does the reverse of grep. I want to match the files in a directory/subdirectory that doesn't have a "searched_string".

到目前为止，我已经做到了:

So far i've done that:

import os

filefilter = ['java','.jsp'] 
path= "/home/patate/code/project"
for path, subdirs, files in os.walk(path):
    for name in files:
        if name[-4:] in filefilter :
        print os.path.join(path, name)

这个小脚本将列出每个子目录中带有java"或jsp"扩展名的每个文件，并输出它们的完整路径.

This small script will be listing everyfiles with "java" or "jsp" extension inside each subdirectory, and will output them full path.

我现在想知道如何做其余的工作，例如，如果我忘记了一个文件中的会话管理条目(允许任何人直接访问文件)，我希望能够搜索:"if (!user.hasPermission" 并列出不包含此字符串的文件.

I'm now wondering how to do the rest, for example i would like to be able if I forgot a session management entry in one file (allowing anyone a direct file access), to search for : "if (!user.hasPermission" and list the file which does not contain this string.

任何帮助将不胜感激！

谢谢

推荐答案

检查路径绑定到变量 f 的文件是否包含绑定到 name s 的字符串, 最简单的(对于大多数合理大小的文件都可以接受)就像

To check if a file with a path bound to variable f contains a string bound to name s, simplest (and acceptable for most reasonably-sized files) is something like

with open(f) as fp:
    if s in fp.read():
        print '%s has the string' % f
    else:
        print '%s doesn't have the string' % f

在你的 os.walk 循环中，你分别有根路径和文件名，所以

In your os.walk loop, you have the root path and filename separately, so

f = os.path.join(path, name)

(您无条件打印的)是您要打开和检查的路径.

(what you're unconditionally printing) is the path you want to open and check.

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