异常数组不衰变成一个指针？ [英] Exception to array not decaying into a pointer?
问题描述
我很多帖子已经看到，在大多数情况下数组名称衰变为指针。结果我能知道在何种情况下/ EX pressions数组名称不衰变成指针第一要素？
I have seen in many posts that "in most of the cases array names decay into pointers".
Can I know in what cases/expressions the array name doesn't decay into pointers to first elements?
推荐答案
当然可以。
在C99有三种基本的情况，分别是：
In C99 there are three fundamental cases, namely:
-
在它的
＆放大器的参数;（地址）的运营商
在它的的sizeof 运营商的说法。
在它的文本类型的字符串的char [N + 1] 或宽字符串文字类型的 wchar_t的[N + 1 ] （ N 是字符串的长度），用来初始化数组，如字符海峡[] =富; 或 wchar_t的WSTR [] = L富;
When it's a string literal of type char [N + 1] or a wide string literal of type wchar_t [N + 1] (N is the length of the string) which is used to initialize an array, as in char str[] = "foo"; or wchar_t wstr[] = L"foo";.
此外，C11，新推出的 alignof 运营商不让其数组参数衰变成一个指针无论是。
Furthermore, in C11, the newly introduced alignof operator doesn't let its array argument decay into a pointer either.
在C ++中，有额外的规则，例如，当它通过引用传递
In C++, there are additional rules, for example, when it's passed by reference.
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