正则表达式:匹配第 n 次出现 [英] RegEx: Match nth occurrence

问题描述

我有以下字符串:

<预> <代码> _name = aVlTcWRjVG1YeDhucWdEbVFrN3pSOHZ5QTRjOEJZZmZUZXNIYW1PV2RGOWYrczBhVWRmdVJTMUxYazVBOE8zQ3JNMmNVKzJLM2JJTzFON3FiLzFHUE0xY0pkdz09LS1jbkkwaWoxUUl3YVhMMkhtZHpaOW13PT0 ％" 3D - 57356371d167f"

我想匹配 = 和结尾 " (注意在这之后还有其他引号，所以我不能只选择最后一个 ").

我尝试使用 _name=(.*?)" 但字符串中还有其他引号.有没有办法匹配第三个引号?我试过 _name=(.*?)"{3} 但 {3} 与引号背靠背匹配，即 """

你可以试试这里

解决方案

你可以使用这个正则表达式:

_name=(?:[^"]*"){3}

正则表达式演示

I have the following string:

_name=aVlTcWRjVG1YeDhucWdEbVFrN3pSOHZ5QTRjOEJZZmZUZXNIYW1PV2RGOWYrczBhVWRmdVJTMUxYazVBOE8zQ3JNMmNVKzJLM2JJTzFON3FiLzFHUE0xY0pkdz09LS1jbkkwaWoxUUl3YVhMMkhtZHpaOW13PT0"%"3D--57356371d167f"

I want to match everything between = and the end " (note there are other quotes after this so I can't just select the last ").

I tried using _name=(.*?)" but there are other quotes in the string as well. Is there a way to match the 3rd quote? I tried _name=(.*?)"{3} but the {3} matches for the quotes back to back, i.e. """

You can try it here

解决方案

You can use this regex:

_name=(?:[^"]*"){3}

RegEx Demo

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