用 preg_replace 大写单词的每个首字母 [英] Uppercase each first letter of words with preg_replace
问题描述
所以我将一些句子插入到具有一些自动更正过程的数据库中.下面这句话:
So I have some sentences I am inserting into a database with some auto-correction processes. The following sentence:
$sentence = "Is this dog your's because it can't be mine";
以下代码将每个单词大写,但要确保它不大写缩写(例如 n't):
And the following code to capitalize each word but make sure it doesn't capitalize contractions (eg. n't):
str_replace(
"'S", "'s", preg_replace(
"/(\w+)n'T?/", "$1n't", (
preg_replace(
"/\b[a-z]/e",
'strtoupper("$0")',
ucwords($sentence)
)
)
)
);
回显时,结果如下:
Is This Dog Your's Because It Can't Be Mine
这是我想要它做的,但是,它输入到我的 MySQL 数据库中的是:
This is what I want it to do, however, what it inputs into my MySQL database is:
Is This Dog Your's Because It Can'T Be Mine
我不知道为什么会这样......我假设我在某处搞砸了.
I have no idea why this is happening... I am assuming that I messed something up somewhere.
推荐答案
你当然应该使用 ucwords()
,但这是您使用正则表达式的方式:
You should of course use ucwords()
, but this is how you would do it with a regular expression:
echo preg_replace_callback('/(?<=\s|^)[a-z]/', function($match) {
return strtoupper($match[0]);
}, $sentence);
通过使用lookbehind 断言,在它变成大写之前.
It makes sure that each lower case character is preceded by a space (or start of the sentence) by using a lookbehind assertion, before it's changed to upper case.
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