排序字符串与Java数组 [英] Sorting an array of Strings with Java

问题描述

我想排序字符串使用的compareTo（）的数组。这是我的code：

I am trying to sort an array of Strings using compareTo(). This is my code:

static  String Array[]={" Hello " , " This " , "is ", "Sorting ", "Example"};
String  temp; 

public static void main(String[] args)

{    

 for(int j=0; j<Array.length;j++)
 {
     for (int i=j+1 ; i<Array.length; i++)
     {
         if(Array[i].compareTo(Array[j])<0)
         {
             String temp= Array[j];
             Array[j]= Array[i]; 
             Array[i]=temp;


         }
     }

     System.out.print(Array[j]);
 }
}

现在的输出：您好本例排序是

now output is : Hello This Example Sorting is

我收到了一些成绩，但不是我想要得到的，我的逻辑是正确的有啥错在这里，任何人都可以帮助我吗？

I am getting some result but not the one i want to get , for me logic is right so whats wrong here , anyone can help me please?

推荐答案

您的输出是正确的。表示你好和本开头的白色字符。

Your output is correct. Denote the white characters of " Hello" and " This" at the beginning.

另一个问题是与你的方法，你为什么不使用 Arrays.sort（）方法？

Another issue is with your methodology, why don't you use Arrays.sort() method?

String[] strings = { " Hello ", " This ", "Is ", "Sorting ", "Example" };
Arrays.sort(strings);

数组这里第三个元素是应为是，否则它会持续排序后进来了。因为排序方法内部使用ASCII值元素进行排序。

Here third element of array "is" should be "Is" otherwise it will come in last after sorting. Because sort method internally uses ASCII value to sort elements.

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