将字符串列表转换为包含整数的元组列表 [英] Converting a list of strings, into a list of tuples containing integers

问题描述

我正在将一个 XML 文件解析为一个坐标列表，这是我正在使用的代码行

nodes = [(int(x.text.strip().split(' ')[0]),int(x.text.strip().split(' ')[1]))对于 tree.getroot()[0]] 中的 x

tree.getroot() 将输出类似 [" 100 200", " 40 90", ...]我正在使用该代码去除空格，将其拆分为两个数字，然后将它们转换为整数，但我不禁看着该代码并认为它​​不能很快.关于优化它的任何想法?

解决方案

不.但是可以简化很多.

<预><代码>>>>L = [' 1 2 ', '3 4 ']>>>[元组(int(y) for y in x.split()) for x in L][(1, 2), (3, 4)]

I'm parsing an XML file into a list of coordinates, and this is the line of code I'm using

nodes = [(int(x.text.strip().split(' ')[0]),int(x.text.strip().split(' ')[1])) for x in tree.getroot()[0]]

Where tree.getroot() will output something like [" 100 200", " 40 90", ...] I'm using that code to strip the whitespace, split it into the two numbers, and convert them to integers, but I can't help looking at that code and thinking it just can't be very fast. Any ideas on optimizing it a bit?

解决方案

Nope. But it can be simplified a lot.

>>> L = [' 1 2 ', '3 4 ']
>>> [tuple(int(y) for y in x.split()) for x in L]
[(1, 2), (3, 4)]

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