为什么 Perl 和/bin/sha1 给出不同的结果? [英] Why does Perl and /bin/sha1 give different results?

问题描述

我很困惑为什么以下返回单独的 sHA1

I'm confused as to why the following return separate sHA1s

$ perl -MDigest::SHA1 -E'say Digest::SHA1::sha1_hex("http://i.aultec.com/v/8066/Originals/1FTVX12585NA9832010.jpg");'
e1133fa3b7ea0bfb8ffa4d877932ed6c6fa10cef

$ echo "http://i.aultec.com/v/8066/Originals/1FTVX12585NA9832010.jpg" | sha1sum 
5c3731e83ae0184ed93b595b9f5604863dd331e6  -

哪个是对的?/我/做错了吗?

Which one is right? Am /I/ doing it wrong?

$ perl -MDigest::SHA -E'say Digest::SHA::sha1_hex("http://i.aultec.com/v/8066/Originals/1FTVX12585NA9832010.jpg");'
e1133fa3b7ea0bfb8ffa4d877932ed6c6fa10cef

您可以在后继 (Digest::SHA) 中看到摘要是正确的

You can see the digest is right in the successor (Digest::SHA)

推荐答案

两者都对.您的 echo 命令在末尾包含一个换行符.(并且 perl 字符串没有)尝试使用 echo -n ...

Both are right. Your echo command includes a newline at the end. (and the perl string doesn't) Try with echo -n ...

这篇关于为什么 Perl 和/bin/sha1 给出不同的结果?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！