为什么 perl 将刻度转换为冒号? [英] Why does perl translate a tick into a colon?

问题描述

鉴于此程序:

use strict;
use warnings;

my $zx_size = 32;
my $x = "$zx_size'h0";

Perl 告诉我:

Name "zx_size::h0" used only once: possible typo at concat.pl line 7.
Use of uninitialized value $zx_size::h0 in string at concat.pl line 7.

为什么?

似乎有多种方法可以指定 var 的命名空间.还有其他的吗?

It appears there are multiple ways to specify the namespace of a var. Are there others?

是否可以关闭此行为?

推荐答案

旧的包分隔符是一个单引号 ' ，它最初用于方便 Ada 程序员过渡到 Perl.它被替换为 :: 以提高可读性并简化 C++ 程序员的转换.

The old package delimiter was a single quote ' which was originally used to ease transition to Perl for Ada programmers. It was replaced with :: to be more readable and ease the transition of C++ programmers.

它仍然支持向后兼容，但您可以将标量包装在 {..} 中以使其正确插入.

It is still supported for backwards compatibility, but you can wrap your scalar in {..} to have it interpolate correctly.

my $x = "${zx_size}'h0";

或

my $x = "$zx_size\'h0";

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