部分填充 PIL ImageDraw Line [英] Fill PIL ImageDraw Line partially

问题描述

我正在尝试用不同的颜色填充一条线，越来越像进度条.这是图片:

I'm trying to fill a line by a different color increasingly like a progress bar. This is the image:

它是用这个代码创建的

from PIL import Image, ImageDraw

image = Image.new("RGBA", (300, 300), color="black")
draw = ImageDraw.Draw(image)
width = 7
image_w, image_h = image.size
coord_a = image_w / 2, width
coord_b = width, image_h / 2
coord_c = image_w / 2, image_h - width
coord_d = image_w - width, image_h / 2
draw.line([coord_a, coord_b, coord_c, coord_d, coord_a], fill="red", width=width, joint="curve")
image.show()
image.save("test.png")

我正在尝试用不同的颜色填充它，如下所示:

我应该单独填写每一行并将它们全部合并吗?

I'm trying to fill it with different color like this:

Should I just fill each line separately and combine them all?

推荐答案

有趣的问题！想出实现此目的的方法可能会很有趣.

Interesting question! You could have lots of fun thinking up ways to do this.

1. 按照您的建议，您可以将菱形绘制为四条单独的线.您必须使用 sin/cos 计算红色和蓝色部分相交的点，但这并不难.

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1. 您可以更简单地绘制它，因为正方形的四个边最初是水平和垂直的，然后在完成绘制后将其旋转 45 度到位.我想我会选择这个选项.

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1. 您可以绘制一条长水平的红线，然后以蓝色过度绘制正确的百分比.然后剪成四份，旋转粘贴到黑色方块背景上.

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1. 您可以使用 scikit-image draw.polygon_perimeter() 获取菱形上所有点的坐标，如此处.然后将第一个着色为蓝色，其余为红色.您可以使用形态学扩张使线条更粗.

1. You could get the coordinates of all the points on the rhombus using scikit-image draw.polygon_perimeter() as documented here. Then colour the first however many percent blue and the remainder in red. You could make the lines thicker using morphological dilation.

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