R - 情节错误对象......未找到 [英] R - plotly error object ... not found

问题描述

我尝试运行带有 iris 数据集的示例行给出对象 '...' not found 错误.我需要在我的环境中检查特定的内容吗?

图书馆(情节)p <- plot_ly(iris, x = Petal.Length, y = Petal.Width,color = Species, mode = "markers")

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plot_ly(iris, x = Petal.Length, y = Petal.Width, color = Species, 中的错误:未找到对象Petal.Length"

解决方案

这恰好是已知的

引自 最新的 plotly 文档plotly 4.0 及以上:

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plot_ly() 现在需要一个公式(基本上是一个表达式，但在引用变量时带有 ~ 前缀).你不必使用公式来引用命名空间中存在的对象，但我推荐它，因为它有助于填充合理的轴/指南标题默认值(例如，将 plot_ly(z = 火山) 的输出与plot_ly(z = ~volcano) ).

I try to run a sample line with iris data set gives object '...' not found error. Is there any I need to check specific in my environment?

library(plotly)
p <- plot_ly(iris, x = Petal.Length, y = Petal.Width,color = Species, mode = "markers")

Error in plot_ly(iris, x = Petal.Length, y = Petal.Width, color = Species, : object 'Petal.Length' not found

解决方案

This happen to be known issue reported to plotly. To fix your example you should add tilde "~" to the data frame columns names:

library(plotly)
p <- plot_ly(iris, x = ~Petal.Length, y = ~Petal.Width,color = ~Species, mode = "markers")
p

This should give you:

Quote from the latest plotly doc for plotly 4.0 and above:

plot_ly() now requires a formula (which is basically an expression, but with a ~ prefixed) when referencing variables. You do not have to use a formula to reference objects that exist in the namespace, but I recommend it, since it helps populate sensible axis/guide title defaults (e.g., compare the output of plot_ly(z = volcano) with plot_ly(z = ~volcano) ).

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