声明不安全的固定自定义结构数组的解决方法? [英] Workaround on declaring a unsafe fixed custom struct array?

问题描述

对于错误 CS1663(固定大小的缓冲区类型必须是以下之一:bool、byte、short、int、long、char、sbyte、ushort、uint、ulong、float 或 double.")是否有任何解决方法.?

Is there any workaround for the error CS1663 ("Fixed size buffer type must be one of the following: bool, byte, short, int, long, char, sbyte, ushort, uint, ulong, float or double.")?

我需要从另一个 blittable 自定义类型结构声明一个不安全的固定数组，但我陷入了这个编译器错误.

I need to declare a unsafe fixed array from another blittable custom type struct but I'm stuck in this compiler error.

显示一些代码来阐明下面的问题.

Showing some code to elucidate the problem below.

struct s1
{
    byte _b1;
    byte _b2;
}

unsafe struct s2
{
    fixed s1 _s1[5]; // CS1663 here...
}

请注意，这两个结构体是 blittable，因此该错误对我没有任何意义.

Note that the two structs are blittable, so the error doesn't make any sense for me.

有人知道我能做什么吗?

Anyone have any idea about what I could do?

谢谢.

推荐答案

另一种解决方法是使用指针类型字段.

Another workaround is to either use pointer type fields.

public struct Foo
{
    public byte _b1;
    public byte _b2;
}

public unsafe struct Bar
{
    public int Length;
    public unsafe Foo* Data;
}

或者，如果您的意图是连续创建一个包含其所有数据的单一值类型对象(即，它可以在非托管代码中被 memcpy'd)——那么唯一的方法是通过根本不使用任何数组.

Alternately, if your intention was to make a single value type object which contains all of its own data, contiguously (ie, so it can be memcpy'd in unmanaged code) -- then the only way to do that is by not using any arrays at all.

public struct Foo
{
    public byte _b1;
    public byte _b2;
}

public struct Bar1
{
    public Foo F1;
}

public struct Bar2
{
    public Foo F1;
    public Foo F2;
}

public struct Bar3
{
    public Foo F1;
    public Foo F2;
    public Foo F3;
}

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