并排排序2 NSArrays在一起边 [英] Sorting two NSArrays together side by side

问题描述

我有需要并排排序侧多个数组。

例如，第一阵列的名称： @ [@乔，@安娜，@迈克尔，@金] ，和
另一个数组保存地址： @ [@好莱坞BLD，@一些街道3，@其他街道，@乡村公路] ，其中阵列指标一起去。 乔住在好莱坞BLD等。

我想的名字按字母顺序排列排序，然后有地址阵列排列一起，使他们仍然走在一起，好莱坞BLD有相同的索引乔。我知道如何排序一个数组的字母

  NSSortDescriptor *排序= [NSSortDescriptor sortDescriptorWithKey：@名升：NO];
[myArray的sortUsingDescriptors：[NSArray的arrayWithObject：排序]];
 

但有越来越采用适当的顺序第二个数组排序任何简单的方法？

解决方案

1. 创建一个排列阵列，最初设置为 P [i] = I


2. 按排序置换是第一组的名称键


3. 使用置换重新排序两个数组

例如：让我们说第一个数组是 {快，棕色，狐狸精} 。置换开始为 {0，1，2} ，并成为 {1，2，0} 排序后。现在，你可以通过置换阵列，并重新排序原阵列和第二阵列需要。

 的NSArray *第一= [NSArray的arrayWithObjects：@快，@棕色，@狐狸，@跳跃，零]
NSArray的*秒= [NSArray的arrayWithObjects：@杰克，@爱，@我的，@狮身人面像零]
NSMutableArray里* P = [NSMutableArray的arrayWithCapacity：first.count];
对于（NSUInteger我！= 0; i = first.count;我++）{
    [P ADDOBJECT：[NSNumber的numberWithInteger：我]];
}
[P sortWithOptions：0 usingComparator：^ NSComparisonResult（ID OBJ1，ID OBJ2）{
    //修改该使用[第一objectAtIndex：[OBJ1的intValue]。name属性
    * NSString的LHS = [第一objectAtIndex：[OBJ1的intValue];
    //同样适用于下一行：使用名称
    * NSString的RHS = [第一objectAtIndex：[OBJ2的intValue];
    返回[LHS比较：RHS];
}];
NSMutableArray里* sortedFirst = [NSMutableArray的arrayWithCapacity：first.count];
NSMutableArray里* sortedSecond = [NSMutableArray的arrayWithCapacity：first.count];
[P enumerateObjectsUsingBlock：^（ID OBJ，NSUInteger IDX，BOOL *停止）{
    NSUInteger POS = [OBJ的intValue];
    [sortedFirst ADDOBJECT：[第一objectAtIndex：POS]];
    [sortedSecond ADDOBJECT：[第二objectAtIndex：POS]];
}];
的NSLog（@％@，sortedFirst）;
的NSLog（@％@，sortedSecond）;
 

I have several arrays that need to be sorted side by side.

For example, the first array has names: @[@"Joe", @"Anna", @"Michael", @"Kim"], and and the other array holds addresses: @[@"Hollywood bld", @"Some street 3", @"That other street", @"country road"], where the arrays' indexes go together. "Joe" lives at "Hollywood bld" and so on.

I would like to sort the names array alphabetically, and then have the address array sorted alongside so they still go together, with "Hollywood bld" having same index as "Joe". I know how to sort one array alphabetical with

NSSortDescriptor *sort=[NSSortDescriptor sortDescriptorWithKey:@"name" ascending:NO];
[myArray sortUsingDescriptors:[NSArray arrayWithObject:sort]];

But is there any easy way of getting the second array sorted using the appropriate order?

解决方案

1. Create a permutation array, initially set to p[i]=i
2. Sort the permutation according to the name key of the first array
3. Use the permutation to re-order both arrays

Example: let's say the first array is {"quick", "brown", "fox"}. The permutation starts as {0, 1, 2}, and becomes {1, 2, 0} after the sort. Now you can go through the permutation array, and re-order the original array and the second array as needed.

NSArray *first = [NSArray arrayWithObjects: @"quick", @"brown", @"fox", @"jumps", nil];
NSArray *second = [NSArray arrayWithObjects: @"jack", @"loves", @"my", @"sphinx", nil];
NSMutableArray *p = [NSMutableArray arrayWithCapacity:first.count];
for (NSUInteger i = 0 ; i != first.count ; i++) {
    [p addObject:[NSNumber numberWithInteger:i]];
}
[p sortWithOptions:0 usingComparator:^NSComparisonResult(id obj1, id obj2) {
    // Modify this to use [first objectAtIndex:[obj1 intValue]].name property
    NSString *lhs = [first objectAtIndex:[obj1 intValue]];
    // Same goes for the next line: use the name
    NSString *rhs = [first objectAtIndex:[obj2 intValue]];
    return [lhs compare:rhs];
}];
NSMutableArray *sortedFirst = [NSMutableArray arrayWithCapacity:first.count];
NSMutableArray *sortedSecond = [NSMutableArray arrayWithCapacity:first.count];
[p enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    NSUInteger pos = [obj intValue];
    [sortedFirst addObject:[first objectAtIndex:pos]];
    [sortedSecond addObject:[second objectAtIndex:pos]];
}];
NSLog(@"%@", sortedFirst);
NSLog(@"%@", sortedSecond);

这篇关于并排排序2 NSArrays在一起边的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！