通过“本地"反对后台工作 [英] Passing "native" object to background jobs

问题描述

这是我想以一种或另一种方式实现的目标.

Here is what I'd like to achieve in one way or another.

我有一个自定义程序集定义了一些对象.在我的脚本中，我创建了一个我想传递给脚本块的自定义对象，并保持该对象的行为.

I have a custom assembly defining some objects. In my script, I create a custom object that I'd like to pass to a script block, keeping that object behavior.

Add-Type -AssemblyName MyCustomDLL

$global:object = new-object MyCustomDLL.MyCustomObject()
$object | gm

$jobWork = { param ($object) $object | gm } # I'd like to keep my object behavior in that block

$job = Start-Job -ScriptBlock $jobWork -ArgumentList $object
Wait-Job $job
Receive-Job $job

我怎样才能做到这一点或达到同样的效果?感谢您的帮助

How can I do that or achieve the same effect? Thanks for your help

推荐答案

您可以使用 PowerShell 和 BeginInvoke、EndInvoke 代替后台作业.这是一个简单但有效的示例，它在作业"中传递活动对象，在那里更改它，获得结果:

Instead of background jobs you may use PowerShell with BeginInvoke, EndInvoke. Here is the simple but working example of passing a live object in a "job", changing it there, getting the results:

# live object to be passed in a job and changed there
$liveObject = @{ data = 42}

# job script
$script = {
    param($p1)
    $p1.data # some output (42)
    $p1.data = 3.14 # change the live object data
}

# create and start the job
$p = [PowerShell]::Create()
$null = $p.AddScript($script).AddArgument($liveObject)
$job = $p.BeginInvoke()

# wait for it to complete
$done = $job.AsyncWaitHandle.WaitOne()

# get the output, this line prints 42
$p.EndInvoke($job)

# show the changed live object (data = 3.14)
$liveObject

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