删除脚本中的别名 [英] Remove alias in script

问题描述

我可以像这样删除别名:

删除项目别名:wget

然后尝试别名给出了预期的结果:

PS >获取wget :术语wget"不被识别为 cmdlet、函数、脚本文件或可运行的程序.

但是，如果我将相同的内容放入脚本中，

PS >猫 wget.ps1删除项目别名:wget获取

它给出了意想不到的结果

cmdlet Invoke-WebRequest 在命令管道位置 1提供以下参数的值:乌里:

解决方案

以下似乎有效

If (Test-Path Alias:wget) {Remove-Item Alias:wget}If (Test-Path Alias:wget) {Remove-Item Alias:wget}获取

第一行删除了 Script 级别的别名，第二行删除了 Global 级别的别名.请注意，两者都需要进行测试，因为如果 Global 不存在，则不会创建 Script.

这也是一种错误行为，因为它在没有点源的情况下修改了父级.

或者，您可以直接点源您的原件，这样就行了

<预><代码>..\wget.ps1

I can remove an alias like so:

Remove-Item Alias:wget

Then trying the alias gives the expected result:

PS > wget
wget : The term 'wget' is not recognized as the name of a cmdlet, function,
script file, or operable program.

However, if I put the same into a script,

PS > cat wget.ps1
Remove-Item Alias:wget
wget

it gives unexpected result

cmdlet Invoke-WebRequest at command pipeline position 1
Supply values for the following parameters:
Uri:

解决方案

The following seems to work

If (Test-Path Alias:wget) {Remove-Item Alias:wget}
If (Test-Path Alias:wget) {Remove-Item Alias:wget}
wget

The first line removes the Script level alias, and the second removes the Global level alias. Note that both need to be tested, because if the Global doesn't exist the Script isn't created.

Also this misbehaves in that it modifies the parent without being dot sourced.

Alternatively you can just dot source your original and that would work

. .\wget.ps1

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