更改脚本以不同方式导出组和嵌套对象 [英] Change the script to export Groups and nested objects differently
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问题描述
我创建了一个类似的脚本:
I created a similiar script like that:
$Groups = Get-QADGroup
$Result = @()
$Groups | ForEach-Object {
$Group = $_
$Members = Get-QADGroupMember $Group -Indirect | ? objectClass -eq "user"
$Obj = '' | Select-Object -Property Name, Members
$Obj.Name = $Group.Name
$Obj.Members = ($Members | % {$_.SamAccountName + "_" + 'Test'})
$Result += $Obj
}
$Result | Export-Csv -Path C:\Temp\groups.csv -NoTypeInformation -Encoding Unicode -Delimiter ";"
输出看起来像这样(示例数据):
The output looks something like this (example data):
"Name";"Members"
"RootGroup01";"Subuser01_Test";"Subuser02_Test";"Subuser03_Test"
"RootGroup02";"Subuser02_Test"
"RootGroup03";"Subuser01_Test";"Subuser02_Test";"Subuser04_Test";
是否可以更改脚本,我会得到这样的结果?:
Is it possible to change the script, that I get something like this?:
"RootGroup01";"RootGroup02";"RootGroup03"
"Subuser01_Test";"Subuser02_Test";"Subuser01_Test"
"Subuser02_Test";;"Subuser02_Test"
"Subuser03_Test";;"Subuser04_Test"
组名应该是标题,所属用户在右列中.如果没有用户,则列单元格保持为空.
The group names should be the header and the belonging users are in the right column. If there is no user, the column cell just stays empty.
推荐答案
你可以编写这样的函数来转置你的数据:
You can write such function to transpose your data:
function Transpose-Data{
param(
[String[]]$Names,
[Object[][]]$Data
)
for($i = 0;; ++$i){
$Props = [ordered]@{}
for($j = 0; $j -lt $Data.Length; ++$j){
if($i -lt $Data[$j].Length){
$Props.Add($Names[$j], $Data[$j][$i])
}
}
if(!$Props.get_Count()){
break
}
[PSCustomObject]$Props
}
}
然后通过以下方式调用它:
Then you invoke it in the following way:
$Groups = @(Get-QADGroup)
$Members = @(
$Groups | ForEach-Object {
,@(
Get-QADGroupMember $_ -Indirect |
? objectClass -eq user |
% {$_.SamAccountName + "_" + 'Test'}
)
}
)
Transpose-Data $Groups.Name $Members |
Export-Csv -Path C:\Temp\groups.csv -NoTypeInformation -Encoding Unicode -Delimiter ";"
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