如何从命令行运行 Powershell 脚本并将目录作为参数传递 [英] How to run a Powershell script from the command line and pass a directory as a parameter

问题描述

PowerShell -Command .\Foo.ps1

• Foo.ps1:

  Function Foo($directory)
  {
      echo $directory
  }
  
  if ($args.Length -eq 0)
  {
      echo "Usage: Foo <directory>"
  }
  else
  {
      Foo($args[0])
  }
  

  尽管 Foo.ps1 位于我调用 Powershell 的目录中，但结果是:

  Despite Foo.ps1 being in the directory from where I am calling Powershell, this results in:

  The term '.\Foo.ps1' is not recognized as the name of a cmdlet, function, script file, or operable program. 
  Check the spelling of the name, or if a path was included, verify that the path is correct and try again.
  

  • 由于 profile.ps1 包含 cd C:\
  ，PowerShell 正在更改目录，因此无法工作
  • Wasn't working because PowerShell was changing directory due to profile.ps1 containing cd C:\

  
  然后我尝试调用它，指定脚本文件的完整路径，但无论我尝试什么，我都无法让它工作.我相信我必须引用路径，因为它包含空格，文件名也是如此，我需要将参数传递给脚本.

  • 目前最好的猜测:

  • Best guess so far:

  PowerShell -Command "'C:\Dummy Directory 1\Foo.ps1' 'C:\Dummy Directory 2\File.txt'"
  

  输出错误:

  Unexpected token 'C:\Dummy Directory 2\File.txt' in expression or statement. 
  At line:1 char:136.
  

  推荐答案

  试试这个:

  powershell "C:\Dummy Directory 1\Foo.ps1 'C:\Dummy Directory 2\File.txt'"
  

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