带有空格的Powershell打开文件路径 [英] Powershell opening file path with whitespaces

问题描述

我是我的 PS 脚本，我希望能够通过执行以下操作在另一个 PS 实例中运行另一个脚本:

I'm my PS script I want to be able to run another script in another PS instance by doing the following:

$filepath = Resolve-Path "destruct.ps1"
    
start-process powershell.exe "$filepath"

destruct.ps1 与此脚本位于同一文件夹中.

destruct.ps1 is in the same folder as this script.

但是，在包含空格的位置 ("C:\My Scripts\") 中运行此脚本时，我将收到以下错误:

However when running this script in a location which includes spaces ("C:\My Scripts\") I will get the following error:

术语C:\My"未被识别为 cmdlet、函数、可运行程序或脚本文件.验证条款并重试.

The term 'C:\My' is not recognized as a cmdlet, function, operable program, or script file. Verify the term and try again.

我知道通过将 '&' 与 Invoke-Expression 方法结合使用可以解决这个问题，但使用 start-process 方法如何才能做到这一点?

I know by using a '&' with the Invoke-Expression method solves this problem, how can I do the same but by using the start-process method?

推荐答案

试试这个:

 start-process -FilePath powershell.exe -ArgumentList "-file `"$filepath`""

评论后

start-process -FilePath powershell.exe -ArgumentList "-file `"$($filepath.path)`""

附注:

$filepath 是 [pathinfo] 类型而不是 [string] 类型.

$filepath is a [pathinfo] type and not a [string] type.

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