替换字符串中最后一次出现的子字符串 [英] Replacing last occurrence of substring in string

问题描述

如何替换字符串中子字符串的最后次出现?

How can you replace the last occurrence of a substring in a string?

推荐答案

正则表达式也可以执行此任务.这是一个可行的示例.它将最后一次出现的Aquarius"替换为Bumblebee Joe"

Regular Expressions can also perform this task. Here is an example of one that would work. It will replace the last occurrence of "Aquarius" with "Bumblebee Joe"

$text = "This is the dawning of the age of Aquarius. The age of Aquarius, Aquarius, Aquarius, Aquarius, Aquarius"
$text -replace "(.*)Aquarius(.*)", '$1Bumblebee Joe$2'
This is the dawning of the age of Aquarius. The age of Aquarius, Aquarius, Aquarius, Aquarius, Bumblebee Joe

贪婪量词确保它尽其所能，直到 Aquarius 的最后一场比赛.$1 和 $2 代表匹配前后的数据.

The greedy quantifier ensure that it take everything it can up until the last match of Aquarius. The $1 and $2 represent the data before and after that match.

如果您使用变量进行替换，则需要使用双引号并将 $ 转义为正则表达式替换，以便 PowerShell 不会尝试将它们视为变量

If you are using a variable for the replacement you need to use double quotes and escape the $ for the regex replacements so PowerShell does not try to treat them as a variable

$replace = "Bumblebee Joe"
$text -replace "(.*)Aquarius(.*)", "`$1$replace`$2"

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