如何在 PowerShell 中的函数结束时返回用户菜单 [英] How to return to user menu at the end of a function in PowerShell

问题描述

我正在编写一个 PowerShell 脚本，它为用户提供了许多可供选择的选项.一旦选择了一个选项，就会执行一个功能，用户将返回到原始菜单.

I am writing a PowerShell script that gives the user a number of options to select from. Once an option is selected, a function is executed and the user is returned back to the original menu.

在下面的代码中，为用户提供了选项，并执行了函数，但完成后，脚本就结束了.我想要的是在函数结束时返回原始用户菜单.有人能告诉我怎么做吗?谢谢！

In the code below, the user is given the options, and the functions are executed, but when complete, the script just ends. What I want instead is at the end of the function to return to the original user menu. Can someone tell me how to do this? Thanks!

function firstFunction {
    Write-Host "You chose option 1"
    return
}

Write-Host "Welcome"

[int]$userMenuChoice = 0
while ( $userMenuChoice -lt 1 -or $userMenuChoice -gt 4){
    Write-Host "1. Menu Option 1"
    Write-Host "2. Menu Option 2"
    Write-Host "3. Menu Option 3"
    Write-Host "4. Quit and Exit"

[int]$userMenuChoice = Read-Host "Please choose an option"}
switch ($userMenuChoice) {
    1{firstFunction}
    2{Write-Host "You chose option 2"}
    3{Write-Host "You chose option 3"}
default {Write-Host "Nothing selected"}
}

推荐答案

将菜单代码放入一个外部循环中，除非 $userMenuChoice 为 4，否则不会终止:

Put the menu code into an outer loop that doesn't terminate unless $userMenuChoice is 4:

do {
  [int]$userMenuChoice = 0
  while ( $userMenuChoice -lt 1 -or $userMenuChoice -gt 4) {
    Write-Host "1. Menu Option 1"
    Write-Host "2. Menu Option 2"
    Write-Host "3. Menu Option 3"
    Write-Host "4. Quit and Exit"

    [int]$userMenuChoice = Read-Host "Please choose an option"

    switch ($userMenuChoice) {
      1{firstFunction}
      2{Write-Host "You chose option 2"}
      3{Write-Host "You chose option 3"}
      default {Write-Host "Nothing selected"}
    }
  }
} while ( $userMenuChoice -ne 4 )

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