获取重复值的键数组 [英] Get the keys for duplicate values in an array

问题描述

如果我阵列是

 阵列（[0] =＆GT; 2011-06-21 [1] =＆GT; 2011-06-22 [2] =＆GT; 2011-06-22 [3] =＆GT; 2011-06-23 [4] =＆GT;
2011-06-23 [5] =＆GT; 2011-06-24 [6] =＆GT; 2011-06-24 [7] =＆GT; 2011-06-25 [8] =＆GT; 2011-06-25 [9]
= GT; 2011-06-26 [10] =＆GT; 2011-06-26 [11] =＆GT; 2011-06-27 [12] =＆GT; 2011-06-27 [13] =＆GT; 2011-06-
28 [14] =＆GT; 2011-06-29 [15] =＆GT; 2011-06-29 [16] =＆GT; 2011-06-30 [17] =＆GT; 2011-06-30 [18] =＆GT;
2011-07-01 [19] =＆GT; 2011-07-01 [20] =＆GT; 2011-07-02 [21] =＆GT; 2011-07-02 [22] =＆GT; 2011-07-03
[23] =＆GT; 2011-07-03 [24] =＆GT; 2011-07-04 [25] =＆GT; 2011-07-04 [26] =＆GT; 2011-07-05 [27] ​​=＆GT; 2011-
07-05 [28] =＆GT; 2011-07-06 [29] =＆GT; 2011-07-06 [30] =＆GT; 2011-07-07 [31] =＆GT; 2011-07-07）
 

1. 现在，我怎么能显示与重复值的钥匙？
   例如。在这里，函数不应返回（[0]，[13]），因为存在与价值没有重复。


2. 如何找到该值的键，例如2011-06-29，它应该返回[15]，[16]

解决方案

函数get_keys_for_duplicate_values​​（$ my_arr，$干净= FALSE） {
    如果（$干净）{
        返回array_unique（$ my_arr）;
    }    $的DUP = $ new_arr =阵列（）;
    的foreach（$ my_arr为$关键=＆GT; $ VAL）{
      如果（！使用isset（$ new_arr [$ VAL））{
         $ new_arr [$ VAL] = $键;
      }其他{
        如果（使用isset（$的DUP [$ VAL））{
           $的DUP [$ VAL] [] = $键;
        }其他{
           $的DUP [$ VAL] =阵列（$键）;
        }
      }
    }
    返回$ DUP的;
}


显然函数名字有点长;）

现在$的DUP将包含重复的值键入一个多维数组，包含这是一个重复的每一个关键，如果你发送真作为你的第二个参数，它将返回原始数组没有重复的值。

另外，你可以传递原始数组作为参考，而返回它会相应调整您的重复阵列

if my arrays is

Array ( [0] => 2011-06-21 [1] => 2011-06-22 [2] => 2011-06-22 [3] => 2011-06-23 [4] =>
2011-06-23 [5] => 2011-06-24 [6] => 2011-06-24 [7] => 2011-06-25 [8] => 2011-06-25 [9] 
=> 2011-06-26 [10] => 2011-06-26 [11] => 2011-06-27 [12] => 2011-06-27 [13] => 2011-06-  
28 [14] => 2011-06-29 [15] => 2011-06-29 [16] => 2011-06-30 [17] => 2011-06-30 [18] => 
2011-07-01 [19] => 2011-07-01 [20] => 2011-07-02 [21] => 2011-07-02 [22] => 2011-07-03 
[23] => 2011-07-03 [24] => 2011-07-04 [25] => 2011-07-04 [26] => 2011-07-05 [27] => 2011-
07-05 [28] => 2011-07-06 [29] => 2011-07-06 [30] => 2011-07-07 [31] => 2011-07-07 ) 

1. Now how can I display the keys with duplicate values? eg. Here the function should NOT return ([0],[13]) since there are no duplicates with the values.
2. How to find the key for the value , eg."2011-06-29" it should return [15],[16]

解决方案

function get_keys_for_duplicate_values($my_arr, $clean = false) {
    if ($clean) {
        return array_unique($my_arr);
    }

    $dups = $new_arr = array();
    foreach ($my_arr as $key => $val) {
      if (!isset($new_arr[$val])) {
         $new_arr[$val] = $key;
      } else {
        if (isset($dups[$val])) {
           $dups[$val][] = $key;
        } else {
           $dups[$val] = array($key);
        }
      }
    }
    return $dups;
}

obviously the function name is a bit long;)

Now $dups will contain a multidimensional array keyed by the duplicate value, containing each key that was a duplicate, and if you send "true" as your second argument it will return the original array without the duplicate values.

Alternately you could pass the original array as a reference and it would adjust it accordingly while returning your duplicate array

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