分割过错二维数组 [英] segmentation fault for 2D arrays

问题描述

我要定义非常大大小的二维数组。但它给我段错误？

I want to define a 2D array of very big size. But it is giving me segmentation fault?

  #include <stdio.h>

  int main () {
       int i;
       int temp[4000][5000];
      for (i = 0; i < 5; i++)
      {
          printf ("Hello World\n");
      }
  }

任何人都可以请建议我一些其他的方式？有一些问题，内存初始化？在此先感谢

Can anyone please suggest me some other way? Is there some problem with memory initialization? Thanks in advance

推荐答案

您可以分配整个表中只有一个数组，但你将无法使用两个方括号索引来访问数组数据：

You can allocate the whole table in only one array but you won't be able to access array data with indices using two square brackets:

int * temp = malloc(4000*5000*sizeof(int));

访问，其中previously你写温度由[i] [j]的，现在你现在应该计算该指数通过以下方式元素（I，J）

to access the element (i,j) where previously you wrote temp[i][j], now you should now compute the index the following way:

temp[i*5000+j];

和不要忘记释放分配给你的表后记忆：

and do not forget to free the memory allocated for your table afterward:

free(temp);

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