按名称前缀对文件进行分组，然后使用 PowerShell 归档 (zip) 每个组 [英] Group files by name prefix and then archive (zip) each group with PowerShell

问题描述

我有以下情况:

我在一个目录中有大量文件，如下所示:

I have a large number of files in a directory named as thus:

'######_dynamicname_timestamp.xml'

'######_dynamicname_timestamp.xml'

我想按 ###### 将文件分组，然后将分组的文件压缩到以组的 ###### 命名的存档中.在这种情况下，文件名和时间戳并不重要，只有前六位数字.我是 PowerSHell 的新手，还不熟悉命令(cmdlet?).在 ss64 上寻找答案时遇到了 group-object 但我仍然无法正确解决.到目前为止，这是我所得到的:

I want to group the files by ###### then zip the grouped files into an archive named after ###### of the group. In this situation the filename and timestamp are not important, only the first six digits. I am new to PowerSHell and am not familiar with the commands (cmdlets?) just yet. Looking for the answer at ss64 I came across group-object however I still can't get it right. So far this is as all I got:

ls D:\directory\ | select name | group-object name

由于时间戳和动态文件名，每个文件都在自己的单独组中.我需要一种仅按前六位数字分组的方法，然后将这些组传递给 zip 或存档命令.预先感谢您的帮助.

Due to the timestamp and dynamic filename each file is in its own individual group. I need a way to group only by the first six digits then pass those groups to a zip or archive command. Thank you in advance for your assistance.

推荐答案

这个管道应该给你想要的结果/想法如何去做

This pipeline should give you the desired result / the idea how to do it

Get-ChildItem D:\directory | 
    Group-Object -Property { $_.Name.Substring(0, 6) } |
    % { Compress-Archive -Path $_.Group -DestinationPath "$($_.Name).zip" }

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