将变量传递给 Start-Job [英] Passing Variables to Start-Job

问题描述

我必须在这里遗漏一些非常简单的东西.这是一个非常基本的脚本来说明我正在尝试的内容:

I have to be missing something incredibly simple here. Here's a very basic script to illustrate what I'm trying:

$Computers = @('comp1', 'comp2')

$ScriptBlock = {
    New-Item "C:\Temp\$C.txt" -Force
}

Foreach ($C in $Computers)
{
    Start-Job -ScriptBlock $ScriptBlock -ArgumentList $C
}

脚本运行，但 $C 没有通过，所以我的文件夹中只有一个.txt"文件.我在这里忽略了什么简单的事情?

The script runs, but $C is not passed, so i just get a ".txt" file in my folder. What simple thing am I overlooking here?

推荐答案

替换为:

$ScriptBlock = {
    New-Item "C:\Temp\$C.txt" -Force
}

有了这个:

$ScriptBlock = 
{
    param($C)
    New-Item "C:\Temp\$C.txt" -Force
}

注意:当您在参数列表中传递参数时，请确保使用 param 在脚本块内必须接受相同数量的参数.

Note: When you are passing the arguments in the argumentlist , then make sure the same number of arguments have to accepted inside the scriptblock by using param.

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