printf 与 %s 以包含空字符 [英] printf with %s to include null characters

问题描述

我需要连接一些字符串，并且需要包含 NULL 字节.我不想将 '\0' 视为终止字节.我想保存我宝贵的 NULL 字节！

I need to concatenate some strings, and I need to include NULL bytes. I don't want to treat a '\0' as a terminating byte. I want to save my valuable NULL bytes!

在代码示例中，如果

    char *a = "\0hey\0\0";

我需要以输出\0hey\0\0"的格式打印.

I need to printf in a format that will output "\0hey\0\0".

-AUstin

推荐答案

怎么样:

int i;
for(i = 0; i < 4; i++)
    printf("%c", a[i]);

如果您希望在格式字符串中指定 %s 时使用 'printf-like' 函数，您可以将上述代码包含在您自己的函数中.但正如@Neil 所提到的，您将很难找到替代查找空字节来确定字符串长度的方法.为此，我想您可以使用某种转义字符.

If you want a 'printf-like' function to use this when you specify %s in a format string you could include the above code in your own function. But as @Neil mentioned, you'll struggle finding an alternative to looking for null bytes to determine the length of strings. For that I guess you could use some kind of escape character.

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