WPF Prism 请求导航激活错误 [英] WPF Prism Request Navigate activation error
问题描述
参考 StockTraderRI,我在 shell 中创建了一个弹出区域
Referring the StockTraderRI, I created a popup region in my shell
infBehaviors:RegionPopupBehaviors.CreatePopupRegionWithName="{x:Static inf:RegionNames.SecondaryRegion}"
在模块中,我试图将视图加载到弹出窗口
In the module I am trying to load the view to the popup
_regionManager.RequestNavigate(RegionNames.SecondaryRegion, new Uri("/OrderDetailsView", UriKind.Relative));
OrderDetailsView 是 OrderDetailsModule 中的一个视图.此时我收到以下错误
OrderDetailsView is a view within OrderDetailsModule. At this point I am getting the below error
Activation error occurred while trying to get instance of type Object, key "OrderDetailsView"
堆栈跟踪如下所示
at Microsoft.Practices.ServiceLocation.ServiceLocatorImplBase.GetInstance(Type serviceType, String key) in c:\Projects\CommonServiceLocator\main\Microsoft.Practices.ServiceLocation\ServiceLocatorImplBase.cs:line 53
at Microsoft.Practices.ServiceLocation.ServiceLocatorImplBase.GetInstance[TService](String key) in c:\Projects\CommonServiceLocator\main\Microsoft.Practices.ServiceLocation\ServiceLocatorImplBase.cs:line 103
at Prism.Regions.RegionNavigationContentLoader.CreateNewRegionItem(String candidateTargetContract)
知道我可能做错了什么吗?
Any ideas what i might be doing wrong?
推荐答案
您必须为导航注册对象.如果您使用的是 Prism 6,则必须使用 Container.RegisterTypeForNavigation
You must register your objects for navigation. If you are using Prism 6 you must use Container.RegisterTypeForNavigation<OrderDetailsView>();
如果使用 v5 或更低版本,则必须使用 container.RegisterType(typeof(object), typeof(OrderDetailsView), "OrderDetailsView");
If using v5 or less you must use container.RegisterType(typeof(object), typeof(OrderDetailsView), "OrderDetailsView");
如果使用 MEF,您必须在导出属性中提供视图名称:
If using MEF, you must provide the view name in the Export Attribute:
[Export("OrderDetailsView")]
public class OrderDetailsView : UserControl
{ ... }
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