在 node.js 中使用参数生成过程 [英] Spawning process with arguments in node.js

问题描述

我需要从 node.js 生成一个子进程，同时使用 ulimit 来防止它使用太多内存.

I need to spawn a child process from node.js, whilst using ulimit to keep it from using to much memory.

按照文档，让基本的 spawn 工作并不难:child = spawn("coffee", ["app.coffee"]).

Following the docs, it wasn't hard to get the basic spawn working: child = spawn("coffee", ["app.coffee"]).

然而，做我在下面所做的只会让 spawn 安静地死去.

However, doing what I do below just makes the spawn die silently.

child = spawn("ulimit", ["-m 65536;", "coffee app.coffee"])

如果我运行 ulimit -m 65536;咖啡 app.coffee - 它按预期工作.

If I would run ulimit -m 65536; coffee app.coffee - it works as intented.

我在这里做错了什么?

推荐答案

这是两个不同的命令.如果您正在使用 spawn，请不要使用它们.使用单独的子进程.

Those are two different commands. Don't club them if you are using spawn. Use separate child processes.

 child1 = spawn('ulimit', ['-m', '65536']);
 child2 = spawn('coffee', ['app.coffee']);

如果您对输出流不感兴趣(如果您只想缓冲输出)，您可以使用 exec.

If you are not interested in output stream(if you want just buffered output) you can use exec.

var exec = require('child_process').exec,
child;

child = exec('ulimit -m 65536; coffee app.coffee',
  function (error, stdout, stderr) {
    console.log('stdout: ' + stdout);
  }
});

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