C# 捕获 python.exe 输出并将其显示在文本框中 [英] C# capturing python.exe output and displaying it in textbox

问题描述

我已经在这个问题上工作了一段时间.我可以很好地捕获控制台窗口的输出(实时)，但是我无法实时捕获 python 控制台应用程序的输出.我可以在 python 程序运行完成后捕获它的输出，但我不想要那样.我正在使用 system.diagonistics 中的进程.与背景工作者.我只是想将 python26 输出捕获到文本框中.我已经用其他自定义应用程序测试了我的程序，它确实显示了输出(实时).

I have worked on this issue for a while. I can capture the output(live) of the console window just fine, but I can't capture the output of a python console application in real time. I can capture the output of the python program after it has finished running, but i don't want that. I am using process from system.diagonistics. with a background worker. I simply want to capture the python26 output onto a text box. I have tested my program with other custom applications, and it does display the output(live).

请帮忙

谢谢

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Diagnostics;
using System.Threading;
using System.IO;

namespace ProcessDisplayoutput
{
public partial class Form1 : Form
{

    //Delegates

    delegate void AppendTextDelegate(string text);

    public Form1()
    {
        InitializeComponent();
        Worker.DoWork += new DoWorkEventHandler(Worker_DoWork);

    }

    private void StartButton_Click(object sender, EventArgs e)
    {
        ResultTextBox.Clear();
        if (!Worker.IsBusy)
        {
            Worker.RunWorkerAsync();
        }
    }

    public void Worker_DoWork(object sender, DoWorkEventArgs e)
    {
        Process pro = new Process();
        pro.StartInfo.RedirectStandardOutput = true;
        pro.StartInfo.RedirectStandardError = true;
        pro.StartInfo.UseShellExecute = false;
        pro.StartInfo.CreateNoWindow = true;
        pro.EnableRaisingEvents = true;
        pro.OutputDataReceived +=new DataReceivedEventHandler(OnDataReceived);
        pro.ErrorDataReceived +=new DataReceivedEventHandler(OnDataReceived);

        //Test with random program worked,
        //now need to test with python
        //*****************TEST 1: PASSED **************************
        pro.StartInfo.FileName = "C:\\TestProcessOutput.exe";
        //*****************END TEST1*******************************

        //*****************TEST 2: FAILED *************************
        //pro.StartInfo.FileName = "C:\\Python26\\python.exe";
        //pro.StartInfo.Arguments = "\"C:\\Python26\\testScript.py\"";
        //*****************END TEST2 *******************************

        StreamReader sr = null;
        try
        {
            pro.Start();

            pro.BeginOutputReadLine();
            //An alternative option to display the output with the same results
            //sr = pro.StandardOutput;
            //string line = "";
            //while ((line = sr.ReadLine()) != null)
            //{
           //     appendText(line);
           // }

        }

        catch (Exception ex)
        {
            MessageBox.Show(ex.ToString());
        }
    }


    public void OnDataReceived(object sender, DataReceivedEventArgs e)
    {

        if (e.Data != null)
        {
            string temp = (e.Data) + Environment.NewLine;
            appendText(temp);

        }
    }
    public void appendText(string text)
    {
        if (ResultTextBox.InvokeRequired)
        {
            ResultTextBox.Invoke(new AppendTextDelegate(appendText), new object[] { text });
        }
        else
        {
            ResultTextBox.AppendText(text);
        }
    }

推荐答案

我自己刚遇到这个问题，经过大量的试验，对我有用的是使用-u"选项运行 python 进程，它使输出无缓冲.这样，一切正常.

I just ran into this question myself, and after a ton of experimenting, what worked for me was running the python process with the "-u" option, which makes the output unbuffered. With that, everything worked completely fine.

这篇关于C# 捕获 python.exe 输出并将其显示在文本框中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！