如何在量角器中设置单选按钮值 [英] how to set a radio button value in protractor

问题描述

我是 Protractor 的新手，我正在尝试使用 Protractor 设置单选按钮值.我在互联网和 SO 上搜索了徒劳的答案.

I'm new to Protractor, I'm trying to set the radio button value using Protractor. I searched over the internet and the SO for the answers which went vain.

html:

<md-radio-group
            id="radiogrp1"
            name="radiogrp1"
            ng-model="application.myRadioGrp"                
            required>
        <md-radio-button value="N" aria-label="No">No</md-radio-button>
        <md-radio-button value="Y" aria-label="Yes">Yes</md-radio-button>
        <md-radio-button value="M" aria-label="Maybe">May</md-radio-button>
</md-radio-group>

从上面的 html 文件中，我尝试在我的 jasmine it() 中执行时设置 No/Yes/Maybe，并使用如下所示的一些量角器代码:

From the above html file, I tried to set No/Yes/Maybe while executing in my jasmine it() with some Protractor code like shown below:

element.all(by.id('radiogrp1)).get(0).click();

对于上面的代码，它默认只接受 yes.我想专门设置单选组的任何值，即 child(md-radio-button) 像父级的 Yes/No/Maybe(md-radio-grp).我尝试了很多方法，比如绑定、地图等，但没有任何帮助.寻求帮助.提前致谢.

For this above code it default accepts yes alone. I want specifically set any value of radio group i.e., child(md-radio-button) like Yes/No/Maybe of parent(md-radio-grp). I tried in many ways like bind, map etc., but nothing helped really. Looking for help. Thanks in advance.

推荐答案

尝试:

element(by.id('radiogrp1')).all(by.tagName('md-radio-button')).get(0).click();

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