检查量角器中是否存在元素 [英] check if element is present in protractor

问题描述

我有一个角度应用程序，用户可以根据她/他的浏览器缓存获得不同的登录屏幕(非角度).我正在使用量角器编写端到端测试用例，我想设置一个类似这样的条件

I have an angular application where user can get a different login screen(non-angular) based on her/his browser cache. I am writing end to end test cases using protractor and I want to put a condition something like this

if(this element is present)
{
click it
}
else check if this element is pressent
{
click it
}

这是我试过的.

  browser.driver.findElements(by.id('element1')).then(function(result) {
      if (result) {
        browser.driver.findElement(by.id('element1')).click();
      }
      else {
        browser.driver.findElement(by.id('element2')).sendKeys("username");
      }
    }
  );

我的问题是，如果if condition"中的元素不存在，那么我会收到错误Failed: no such element: Unable to locate element:".我不希望我的测试用例失败，因为元素可能不存在，然后它应该转到 else 块.我在stackoverflow上看到了很多问题，但没有任何帮助.我真的很感激这里的任何帮助.

My issue is that if the element in the 'if condition' is not present then I am getting an error ' Failed: no such element: Unable to locate element:'. I don't want my test cases to fail because it's possible that the element is not present and then it should go to else block. I have seen so many questions on stackoverflow but nothing helped me. I would really appreciate any help here.

更新:请注意，这是一个非角度屏幕，我只能使用 browser.driver.______ apis.

Update: please note that this is a non-angular screen and I can only use browser.driver.______ apis.

推荐答案

您走在正确的轨道上.因为 findElements 返回一个数组，所以您只需要将 if (result) 更改为 if (result.length>0).使用 FindElements，什么也找不到不是错误.

You were very much on the right track. Because findElements returns an array, you just needed to change what you had if (result) to if (result.length>0). With FindElements, finding nothing is not an error.

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