F＃：通过分组中的一个元素放入数组中减少元组的列表 [英] F#: Reduce a list of tuples by grouping one of the elements into arrays

问题描述

我有我想组由它的元素作为一个关键的一个元组的列表。举例来说，如果我有元组名单：

I have a list of tuples which i want to group by one of its elements as a key. For example, if i had this list of tuples:

[（A，你好），（A，堆叠），（A，过），（A，流），（B，如何），（B，
  你），（C，干什么）]

[(A, "hello"), (A, "stack"), (A,"over"), (A, "flow"), (B, "how"), (B, "you"), (C, "doin")]

我想在窗体上得到的结果：

I would like to get a result in the form:

[（A，[你好，堆栈，过，流]），（B，[怎么做，你]），（C，
  [干什么]）]

[(A, ["hello", "stack", "over", "flow"]), (B, ["how", "you"]), (C, ["doin"])]

我是新来的F＃，所以我全力以赴就如何做到这一点的想法。我感谢你在前进。

I am new to F# so I am all out of ideas on how to do this. I thank you in advance.

欢呼声

推荐答案

我认为你正在使用不正确分隔符列表中的元素 - 而不是，你需要使用;

I think you are using incorrect delimiter for list elements - instead of , you need to use ;.

要得到结果使用这个片断：

To get results use this snippet:

[("A", "hello"); ("A", "stack"); ("A","over"); ("A", "flow"); ("B", "how"); ("B", "you"); ("C", "doin")]
  |> Seq.groupBy fst 
  |> Seq.map (fun (key,groupping) -> key, (groupping |> Seq.map snd |> Seq.toList)) 
  |> Seq.toList

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